CH.11 - CH.11 11.9 p= i= n 1 2 3 4 5 a) Salvage $10,000.00...

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CH. 11 11.9 p =   $70,000.00  i =  10% n Salvage AOC Cap Recovery Total AW 1  $10,000.00   $(20,000.00)  $(67,000.00)  $(87,000.00) 2  $10,000.00   $(20,000.00)  $(35,571.43)  $(55,571.43) 3  $10,000.00   $(20,000.00)  $(25,126.89)  $(45,126.89) 4  $10,000.00   $(20,000.00)  $(19,928.25)  $(39,928.25) 5  $10,000.00   $(20,000.00)  $(16,827.85)  $(36,827.85) a) p =   $70,000.00  i =  10% n Salvage AOC Cap Recovery AW AOC Total AW 1  $10,000.00   $(20,000.00)  $(67,000.00)  $(20,000.00)  $(87,000.00) 2  $9,000.00   $(23,000.00)  $(36,047.62)  $(21,428.57)  $(57,476.19) 3  $8,000.00   $(26,450.00)  $(25,731.12)  $(22,945.62)  $(48,676.74) 4  $7,000.00   $(30,417.50)  $(20,574.66)  $(24,555.59)  $(45,130.25) 5  $6,000.00   $(34,980.13)  $(17,483.04)  $(26,263.10)  $(43,746.14) 6  $5,000.00   $(40,227.14)  $(15,424.48)  $(28,072.95)  $(43,497.43) 7  $4,000.00   $(46,261.22)  $(13,956.76)  $(29,990.09)  $(43,946.85)
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This note was uploaded on 04/11/2010 for the course MST 502 taught by Professor Atals during the Spring '10 term at SUNY IT.

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CH.11 - CH.11 11.9 p= i= n 1 2 3 4 5 a) Salvage $10,000.00...

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