Final(Case13)

Final(Case13) - Joseph Murphy Case 13 Alt ID 1 2 3 4 Desc...

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Joseph Murphy Case 13 Savings from Discontinuation of Extra Cost for Removal of Alt. ID Desc. Aeration Sludge Total Hardness Turbidity Total Savings 1 Both $- $- $- $- $- $- $- 2 Aeration $- $275.00 $275.00 $1,380.00 $469.00 $1,849.00 $(1,574.00) 3 Sludge $2,196.00 $- $2,196.00 $262.00 $845.00 $1,107.00 $1,089.00 4 Neither $2,196.00 $275.00 $2,471.00 $1,380.00 $469.00 $1,849.00 $622.00 Aeration cost = (40 hp x 0.75 kw/hp x 0.06$/kwh x 24h/day) /0.90 $48.00 per day $1,464.00 per month Savings = 2196 - 1464 = 732 1. If electricty were 0.06$/kwh the monthly savings would only be $732. Aeration cost = (40 hp x 0.75 kw/hp x 0.06$/kwh x 24h/day) /0.80 $54.00 per day $1,647.00 per month Savings = 2196 - 1647 = 549 2. Decreasing the efficiency of the aerator motor makes the selection less attractive by offering lower savings per month.
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Savings from Discontinuation of Extra Cost for Removal of Alt. ID Desc. Aeration Sludge Total Hardness Turbidity Total Savings 1 Both $- $- $- $- $- $- $- 2 Aeration $- $275.00 $275.00 $2,070.00 $469.00 $2,539.00 $(2,264.00)
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This note was uploaded on 04/11/2010 for the course MST 502 taught by Professor Atals during the Spring '10 term at SUNY IT.

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Final(Case13) - Joseph Murphy Case 13 Alt ID 1 2 3 4 Desc...

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