EXPERIMENT 12

EXPERIMENT 12 - EXPERIMENT 12: K inetics Josu J. Negron...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
EXPERIMENT 12:   Kinetics Josué J. Negron “I commit to uphold the ideals of honor and integrity by refusing to betray the trust bestowed upon me as a member of the Georgia Tech community.” Signature: Josué Negron 17:28:28 Lab Partner: Ahmed Ismail Chemistry 1310- H1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
  EXPERIMENT  12 N e g r o n  | 2 Table of Contents Rate = k [cyclohexanone] l [I 3 - ] m [HCl] n
Background image of page 2
  EXPERIMENT  12 N e g r o n  | 3 Part A. DATA & RESULTS (60 points total) Data/Results Table (9 points) Trial [Cyclohexanone] [I 3 - ] [H + ] Time to Clear Rate (mole/ Ls) pH at beginning of reaction pH at end of reaction 1 .167 .0033 .33 3:01:63 1.82x10 -5 2 1 1 .167 .0033 .33 3:09:55 1.74x10 -5 2 1 2 .167 .0033 .167 6:33:12 8.39x10 -6 2 1 3 .083 .0033 .33 5:19:19 1.03x10 -5 2 1 4 .167 .00167 .33 1:43:54 1.61x10 -5 2 1 Sample Calculations: a. (Trial 1) Concentration of I 3 - M 1 V 1 = M 2 V 2 (.02M)(.001L) = M 2 (.006L) M 2 = .0033 b. (Trial 1) Rate Calculation Calculation to obtain reaction order with respect to H + Rate = k [cyclohexanone] l [triiodide] m [H + ] n = [. ] [. ] [. ] [. ] [. ] [. ] ratetrial1ratetrial2 k 167 l 0033 m 33 nk 167 l 0033 m 167 n . - . - = . 1 82x10 58 39x10 6 1 976n = . ~ n 1 14 1 Calculation to obtain reaction order with respect to cyclohexane
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 6

EXPERIMENT 12 - EXPERIMENT 12: K inetics Josu J. Negron...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online