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Unformatted text preview: Kim, Jin Homework 9 Due: Oct 30 2007, 3:00 am Inst: Diane Radin 1 This printout should have 15 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Evaluate the iterated integral I = Z 4 1 n Z 4 2 ( x + y ) 2 dx o dy . 1. I = ln 12 7 2. I = ln 5 2 3. I = 1 2 ln 12 7 4. I = 2 ln 5 2 correct 5. I = 1 2 ln 5 2 6. I = 2 ln 12 7 Explanation: Integrating the inner integral with respect to x keeping y fixed, we see that Z 4 2 ( x + y ) 2 dx = h 2 x + y i 4 = 2 n 1 y 1 4 + y o . In this case I = 2 Z 4 1 n 1 y 1 4 + y o dy = 2 h ln y ln(4 + y ) i 4 1 . Consequently, I = 2 ln (4)(1 + 4) (4 + 4) = 2 ln 5 2 . keywords: iterated integral, rational function, log integral 002 (part 1 of 1) 10 points Evaluate the iterated integral I = Z ln 4 Z ln 3 e 2 x y dx ! dy . 1. I = 4 2. I = 3 correct 3. I = 5 4. I = 2 5. I = 6 Explanation: Integrating with respect to x with y fixed, we see that Z ln 3 e 2 x y dx = 1 2 h e 2 x y i ln 3 = 1 2 e 2 ln 3 y e y = 3 2 1 2 e y . Thus I = 4 Z ln 4 e y dy = 4 h e y i ln 4 = 4 e ln 4 1 . Consequently, I = 4 1 4 1 = 3 . keywords: 003 (part 1 of 1) 10 points Kim, Jin Homework 9 Due: Oct 30 2007, 3:00 am Inst: Diane Radin 2 Determine the value of the double integral I = Z Z A 3 xy 2 9 + x 2 dA over the rectangle A = n ( x, y ) : 0 x 2 , 4 y 4 o , integrating first with respect to y . 1. I = 32 ln 13 18 2. I = 32 ln 13 9 3. I = 64 ln 9 13 4. I = 64 ln 13 18 5. I = 32 ln 9 13 6. I = 64 ln 13 9 correct Explanation: The double integral over the rectangle A can be represented as the iterated integral I = Z 2 Z 4 4 3 xy 2 9 + x 2 dy dx , integrating first with respect to y . Now after integration with respect to y with x fixed, we see that Z 4 4 3 xy 2 9 + x 2 dy = h xy 3 9 + x 2 i 4 4 = 128 x 9 + x 2 . But Z 2 128 x 9 + x 2 dx = h 64 ln(9 + x 2 ) i 2 . Consequently, I = 64 ln 13 9 . keywords: 004 (part 1 of 1) 10 points Evaluate the integral, I , of the function f ( x, y ) = 3 xe 3 xy over the rectangle A = { ( x, y ) : 0 x 3 , y 1 } . 1. I = 1 6 e 9 8 2. I = 1 3 e 9 10 correct 3. I = 1 6 e 9 9 4. I = 1 3 e 9 9 5. I = 1 6 e 9 10 6. I = 1 3 e 9 8 Explanation: The integral is given by I = Z Z A 3 xe 3 xy dxdy. Since the integral with respect to y can be evaluated easily using substitution (or di rectly making the substitution in ones head), while the integral with respect to x requires integration by parts, this suggests that we should represent the double integral as the repeated integral I =...
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 Spring '09
 Turner

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