This preview shows pages 1–4. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Kim, Jin Homework 11 Due: Nov 13 2007, 3:00 am Inst: Diane Radin 1 This printout should have 22 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points If the n th partial sum of an infinite series is S n = 3 n 2 4 2 n 2 + 1 , what is the sum of the series? 1. sum = 9 8 2. sum = 3 2 correct 3. sum = 11 8 4. sum = 5 4 5. sum = 1 Explanation: By definition sum = lim n S n = lim n 3 n 2 4 2 n 2 + 1 . Thus sum = 3 2 . keywords: partial sum, definition of series 002 (part 1 of 1) 10 points If the n th partial sum of n =1 a n is given by S n = 3 n + 5 n + 4 , what is a n when n 2? 1. a n = 7 ( n + 4)( n + 3) correct 2. a n = 17 n ( n + 4) 3. a n = 17 ( n + 4)( n + 3) 4. a n = 7 n ( n + 4) 5. a n = 17 ( n + 4)( n + 5) 6. a n = 7 ( n + 4)( n + 5) Explanation: By definition S n = n X k 1 a n = a 1 + a 2 + ... + a n . Thus, for n 2, a n = S n S n 1 = 3 n + 5 n + 4 3( n 1) + 5 ( n 1) + 4 . Consequently, a n = 7 ( n + 4)( n + 3) . keywords: partial sum, definition of series 003 (part 1 of 1) 10 points Determine whether the series 4 16 3 + 64 9 256 27 + is convergent or divergent, and if convergent, find its sum. 1. series is divergent correct 2. convergent with sum = 9 7 3. convergent with sum = 4 4. convergent with sum = 3 Kim, Jin Homework 11 Due: Nov 13 2007, 3:00 am Inst: Diane Radin 2 5. convergent with sum = 8 7 Explanation: The infinite series 4 16 3 + 64 9 256 27 + = X n = 1 ar n 1 is an infinite geometric series with a = 4 , r = 4 3 . But an infinite geometric series n = 1 ar n 1 (i) converges when  r  < 1 and has sum = a 1 r while it (ii) diverges when  r  1 . Consequently, the given series is divergent . keywords: infinite series, geometric series, di vergent 004 (part 1 of 1) 10 points Determine whether the series X n = 1 5 n 2 n 2 + 3 is convergent or divergent, and if convergent, find its sum. 1. convergent with sum = 1 5 2. convergent with sum = 5 3. divergent correct 4. convergent with sum = 4 5 5. convergent with sum = 5 4 Explanation: The infinite series X n =1 a n is divergent when lim n a n exists but lim n a n 6 = 0 . Note for the given series, a n = 5 n 2 n 2 + 3 = 5 1 + 3 n 2 , so lim n a n = lim n 5 n 2 n 2 + 3 = 5 6 = 0 . Thus the given series is divergent . keywords: 005 (part 1 of 1) 10 points Determine whether the series X n = 0 3 1 5 n is convergent or divergent, and if convergent, find its sum. 1. divergent 2. convergent, sum = 5 2 3. convergent, sum = 15 4 correct 4. convergent, sum = 4 5. convergent, sum = 4 Kim, Jin Homework 11 Due: Nov 13 2007, 3:00 am Inst: Diane Radin 3 Explanation: The given series is an infinite geometric series X n = 0 ar n with a = 3 and r = 1 5 . But the sum of such a series is (i) convergent with sum a 1 r when...
View
Full
Document
 Spring '09
 Turner

Click to edit the document details