hw2 - The position-versus-time graph below de-scribes the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Muraj, Hamza – Homework 2 – Due: Jan 25 2006, 4:00 am – Inst: Florin 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – fnd all choices be±ore answering. The due time is Central time. 001 (part 1 o± 1) 10 points Water ²ows into a swimming pool at the rate o± 13 . 7 gal / min. I± the pool dimensions are 22 . 5 ±t wide, 46 . 2 ±t long and 18 . 9 ±t deep, how long does it take to fll the pool? (1 gallon = 231 cubic inches) Correct answer: 10727 . 5 min. Explanation: Basic Concepts The volume o± the pool is given by V = lwh Solution The ²ow rate is v = V t Thus t = V v = 146966 gal 13 . 7 gal / min = 10727 . 5 min Dimensional analysis V : ±t 3 · µ 12 in ±t 3 · µ 1 gal 231 in 3 = gal 002 (part 1 o± 1) 10 points
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: The position-versus-time graph below de-scribes the motion o three dierent bodies (labelled 1, 2, 3). 1 2 3 x B x A t A t B x t A B Consider the average velocities o the three bodies. Which o the ollowing statements is correct? 1. v 1 < v 2 < v 3 2. v 1 > v 2 > v 3 3. v 1 > v 2 and v 3 > v 2 4. v 1 = v 2 = v 3 correct Explanation: The defnition o average velocity is v = displacement time = x B-x A t B-t A . All three bodies have exactly same displace-ment in exactly same time, hence all three av-erage velocities are exactly equal, v 1 = v 2 = v 3 ....
View Full Document

This note was uploaded on 04/12/2010 for the course PHY 58195 taught by Professor Turner during the Spring '09 term at University of Texas at Austin.

Ask a homework question - tutors are online