HW 04 solution

# HW 04 solution - gutierrez (ig3472) HW04 Neitzke (56585) 1...

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Unformatted text preview: gutierrez (ig3472) HW04 Neitzke (56585) 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 4) 10.0 points A Calculus student begins walking in a straight line from the RLM building towards the PCL Library. After t minutes his velocity v = v ( t ) is given (in multiples of 10 yards per minute) by the function whose graph is 2 4 6 8 10- 2 2 4 6- 2 t v How far is the student from the RLM build- ing at time t = 4? 1. dist = 80 yards 2. dist = 110 yards 3. dist = 90 yards 4. dist = 70 yards correct 5. dist = 60 yards Explanation: The student is walking towards the PCL Library whenever v ( t ) &gt; 0 and towards RLM whenever v ( t ) &lt; 0. The distance he has walked is given by 10 times the area between the graph of v and the t axis since 1 unit is equivalent to 10 yards. Now at t = 4 this area is 7 units, so the student has walked a distance of 70 yards. 002 (part 2 of 4) 10.0 points How far is the student from the RLM build- ing at time t = 8? 1. dist = 230 yards correct 2. dist = 220 yards 3. dist = 250 yards 4. dist = 240 yards 5. dist = 270 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 8 this area is 23 units, so the student has walked a distance of 230 yards. 003 (part 3 of 4) 10.0 points What is the total distance walked by the student from time t = 0 to t = 10? 1. dist = 280 yards 2. dist = 250 yards 3. dist = 260 yards 4. dist = 270 yards correct 5. dist = 300 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 10 this area is 27 units (area is always positive remember), so the student has walked a distance of 270 yards. 004 (part 4 of 4) 10.0 points How far is the student from the RLM build- ing when he turns back? 1. dist = 280 yards 2. dist = 250 yards gutierrez (ig3472) HW04 Neitzke (56585) 2 3. dist = 230 yards 4. dist = 300 yards 5. dist = 260 yards correct Explanation: The student will turn back when his veloc- ity changes from postive to negative, i.e. , at t = 9. At this time he is 260 yards from the RLM building. keywords: distance, time, graph, velocity, area 005 10.0 points A Calculus student begins walking in a straight line from the RLM building towards the PCL Library. After t minutes his velocity v = v ( t ) is given (in multiples of 10 yards per minute) by the function whose graph is 2 4 6 8 10- 2 2 4 6- 2 t v What is the total distance walked by the stu- dent from time t = 0 to t = 10? 1. dist = 200 yards 2. dist = 170 yards 3. dist = 160 yards 4. dist = 180 yards 5. dist = 190 yards correct Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 10 this area is 19 units (area is always positive remember), so the student has walked a distance of 190 yards ....
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## This note was uploaded on 04/13/2010 for the course MATH 408L taught by Professor Gogolev during the Spring '09 term at University of Texas at Austin.

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HW 04 solution - gutierrez (ig3472) HW04 Neitzke (56585) 1...

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