090211_Homework4_answer - Homework 4 Answer (Due 02/11/2009...

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1 Homework 4 Answer (Due 02/11/2009 Wednesday) P2.31, P2.34 P3.2, P3.3, P3.4, P3.7, P3.10, P3.15, P3.16, P3.19, P3.21, P3.22, P3.23, P3.25 P2.31) DNA can be modeled as an elastic rod that can be twisted or bent. Suppose a DNA molecule of length L is bent such that it lies on the arc of a circle of radius R c . The reversible work involved in bending DNA without twisting is w bend = BL 2 R 2 c where B is the bending force constant. The DNA in a nucleosome particle is about 680 Å in length. Nucleosomal DNA is bent around a protein complex called the histone octamer into a circle of radius 55 Å. Calculate the reversible work involved in bending the DNA around the histone octamer if the force constant B = 2.00 × 10 –28 J m. The bending work is given by: ( ) ( ) () J 10 2.25 m 10 55 2 m 10 680 m J 10 2.00 R 2 L B w 19 - 2 10 - -10 -28 2 c bend × = × × × × × = = P2.34) The formalism of Young’s modulus is sometimes used to calculate the reversible work involved in extending or compressing an elastic material. Assume a force F is applied to an elastic rod of cross-sectional area A 0 and length L 0 . As a result of this force, the rod changes in length by Δ L. Young’s modulus E is defined as E = tensile stress tensile strain = F / A 0 Δ L / L 0 = FL 0 A 0 Δ L a. Derive Hooke’s law from the Young’s modulus expression just given.
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2 b. Using your result from part (a), show that the reversible work involved in changing by Δ L the length L 0 of an elastic cylinder of cross-sectional area A 0 is w = 1 2 Δ L L 0 2 EA 0 L 0 . a) Hooke’s law says that the force with which a mass on a spring opposes displacement is directly proportional to the displacement: d k F = Young’s modulus shows the same dependency of the force: L A L F E 0 0 Δ = L k L A L E F 0 0 Δ = Δ = , where k’ is a constant given by: L A E k 0 0 = b) The work is given by the integral: 2 0 0 0 2 0 0 2 L 0 L 0 twist L L L A E 2 1 L L A E 2 1 L k 2 1 ds L k ds F w ⎛ Δ = Δ = Δ = Δ = = Δ Δ P3.2) The function f ( x,y ) is given by f ( x,y ) = xy sin 5 x + x 2 y ln y + 3 e 2 x 2 cos y . Determine f x y , f y x , 2 f x 2 y , 2 f y 2 x , f y f x y x
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3 and x f y x y a. Is y f x y x = x f y x y ? b. Obtain an expression for the total differential df. [] [] [] y Cos e x 12 lny y x 2 5x Sin y 5x Cos y x 5 x f 2 2x y + + = y Sin e 3 y 2 lny x y x 5x Sin x y f 2 2x 2 2 x + + = y Cos e x 48 y Cos e 12 lny y 2 ] 5 [ 5 5x Sin y x 25 5x Cos y 5 x f 2 2 2x 2 2x y 2 2 + + + = x yCos y Cos e 3 2 y 4 lny x y 2 x y f 2 2 3 2 3 2x 2 2 2 x 2 2 + = x [] [ ] y Sin xe 12 y lny x y x 2 x 5 Cos x 5 5x Sin y f x f 2 2x x + + + + =
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This note was uploaded on 04/14/2010 for the course CHEM 340 taught by Professor Yoshitakaishii during the Spring '07 term at University of Illinois, Urbana Champaign.

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090211_Homework4_answer - Homework 4 Answer (Due 02/11/2009...

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