This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Or use the results of the previous problem to set up the 2x2 secular determinant and solve the resulting quadratic equation for E. In the latter case, you get two solutions, one for the bonding orbital and one for the antibonding one. 4. (Problem 9-12 in McQuarrie and Simon) Use simple molecular-orbital theory to explain why the dissociation energy of N 2 is treater than that of N 2 + , but that the dissociation energy of O 2 + is greater than that of O 2 . This is a freshman chemistry question about bond order. 5. (Problem 9-23 in McQuarrie and Simon) See your book for the text of the problem. This problem simply asks you to quantify the basic idea behind photoelectron spectroscopy, as shown in Figures 9.16 and 9.17 of the text....
View Full Document
This note was uploaded on 04/19/2010 for the course ECH 161B taught by Professor Phillips during the Spring '10 term at UC Davis.
- Spring '10