{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

P-N Junction Diode - Luke Wyatt P-N Junction Diode P-N...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Luke Wyatt P-N Junction Diode 02/11/07 P-N Junction Diode Risk Assessment 1. Electrical Results dc Voltage diode V (V) 100 V (V) I (A) X c (Ω) C (pF) 2 1 C (pF²) 0 500m 1m 10 μ 50k 1.27 0.617 x 12 10 -1 500m 0.5m 5 μ 100k 0.636 2.47 x 12 10 -2 500m 0.4m 4 μ 125k 0.509 3.86 x 12 10 -3 500m 0.4m 4 μ 125k 0.509 3.86 x 12 10 -4 500m 0.3m 3 μ 167k7 0.382 6.85 x 12 10 -5 500m 0.3m 3 μ 166k7 0.382 6.85 x 12 10 -6 500m 0.3m 3 μ 166k7 0.382 6.85 x 12 10 -7 500m 0.2m 2 μ 250k 0.255 15.42 x 12 10 -8 500m 0.2m 250k 0.255 15.42 x 12 10 Calculations 3 6 100 1 10 10 10 100 100 V x I X A - - = = = 3 6 500 10 50 10 10 diode c V x X K I x - - = = = 12 6 3 1 1 1.27 10 1.27 2 2 10 50 10 c C X F pF fX x π π - = = = = 23 2 11 2 2 12 2 1 1 6.17 10 6.17 10 (1.27 10 ) X F X pF C X - = = = 1 of 3
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Luke Wyatt P-N Junction Diode 02/11/07 2 of 3
Image of page 2
Luke Wyatt P-N Junction Diode 02/11/07 Calculations 24 2 1 8.57 10 X C δ = ( ) 1 V δ = 24 8.57 10 1 X gradient = where 19 10 0 2 16 4 1.6 10 1.053 10 / 10 s q X X F m A m ε ε - - - = = = 20 3 2 19 10 16 24 0 2 2 1.38 10 1.6 10 1.053 10 10 8.57 10 D s N X m q A gradient X X X ε ε - - - - = = = Voltage Range Gradient Doping concentration (m 3 - ) -8 to -5 V 2.86x10 24 4.15x10 20 -5 to -2 V 9.97x10 23 1.19x10 21 Errors There were some errors in the collection of the results. Firstly there was an error in reading the oscilloscope correctly. There was lots of noise interference on both
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern