2.133 Given: An astronaut is jogging on the moon and tries to stop. µ = 0.3. g m = (1/6)g e . L0 = mv0 = (5 slugs)(12 ft/s). (Although the problem doesn’t say it explicitly, I will assume the mass m = 5 slugs.) Find: ∆ t needed to stop as compared to on the moon. Solution: Use Impulse = change in momentum 1 2 2 1 L L F I − = = ∫ t t dt () ( ) 1 2 /
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