{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# 68&amp;71 - TAM 212 Spring 2004 1.68 Given The bar of...

This preview shows page 1. Sign up to view the full content.

TAM 212 Spring, 2004 1.68 Given: The bar of length 2L leans up against a vertical wall. It makes an angle q with the horizontal. Required: The velocity and acceleration of the center of the bar as a function of q and its derivatives. (Essentially, we are solving for the velocity and acceleration of C, assuming we might know q and its derivatives, as functions of time.) Solution: We first need to express j i r OC OC OC y x + = , where O is some fixed point (origin). Let’s chose the origin to be where the floor meets the wall. If you can’t picture the expression for the position for C immediately, it may be simpler to first think of point B where, B is where the bar touches the floor. ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 j i i j i j i r r r q q q sin cos 0 cos 2 L L L y x y x BC BC OB OB BC OB OC + - + + = + + + = + = ( 29 ( 29 j i r q q sin cos L L OC + = , so q q sin ; cos L y L x OC OC = = 1.27, 1.28 give us: j i v OC OC OC y x & & + = and j i a OC OC OC y x & & & & + = So we simply take derivatives (w.r.t. time) of q q sin ; cos L y L x OC OC = = to get ( 29 ( 29 ( 29 [ ] ( 29 ( 29 ( 29 [ ] q q q q q q q q q q q q & & & & & & & & & & & & & & cos sin ; cos ; sin cos ; sin 2 2 + - = = + - = - = L y L y L x L x OC OC OC OC So… ( 29 ( 29 ( 29 ( 29 ( 29 [ ] ( 29 ( 29 [ ] j i a j i v q q q q q q q q q q q q & & & & & & & & cos sin sin cos ; cos sin
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern