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Populatio_25955 - 1 Population Genetics 1 What are the...

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1 Population Genetics 1. What are the genotypic frequencies in a population composed of the following 312 AA, 361 Aa, 242 aa individuals? Total # of individuals in population = 312 + 361 + 242 = 915 Frequency of AA = 312/915 = 0.34 Frequency of Aa = 361/915 = 0.40 Frequency of aa = 242/915 = 0.26 2. In a population of 200 mice, 98 are homozygous dominant for brown coat color (BB), 84 are heterozygous (Bb), and 18 are homozygous recessive (bb). a. What are the allele frequencies in this population for the B allele and b allele? 200 mice x 2 alleles per mouse = 400 B, b alleles 98 BB = 98 x 2 B alleles = 196 B alleles 84 Bb = 84 x 1 B allele = 84 B alleles 280 B alleles; 280/400 total alleles = 0.7 = frequency of B allele 84 Bb = 84 x 1 b allele = 84 b alleles 18 bb = 18 x 2 b alleles = 36 b alleles 120 b alleles; 120/400 total alleles = 0.3 = frequency of b allele b. The genotype frequencies of this population are: BB = 98/200 = 0.49 Bb = 84/200 = 0.42 bb = 18/200 = 0.09 3. Use the allele frequencies you determined in question 3 to predict the genotype frequencies of the next generation. Frequencies of: B (p): p 2 = genotype frequency of BB = 0.49; p = 0.7 b (q) = q 2 = genotype frequency of bb = 0.09; q = 0.3 BB = p 2 = (0.7) 2 = 0.49 Bb = 2pq = 2(0.7)(0.3) = 0.42
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