09F-quiz-1-sol

09F-quiz-1-sol - ECE65 (Fall 2009), Quiz 1 Notes: 1. Write...

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Notes: 1. Write your answers on these three sheets. 2. For each problem, 20% of points are alloacted for the correct ±nal answer. Problem 1. For the circuit below with a Si diode, derive the expression for v o for - 5 v i 5 (10 pts). v i v o i D i D 2 V 1k KVL: v i = 10 3 i D + v D + 2 KVL: v i = 10 3 i D + v o v o = v i - 10 3 i D = v D + 2 Case 1: Diode is ON: v D = v γ = 0 . 7 V and i D 0. Then, from KVLs above, v o = v D + 2 = 2 . 7 V. To ±nd when the diode is ON ( i D 0): v i = 10 3 i D + 0 . 7 + 2 i D = 10 - 3 ( v i - 2 . 7) 0 v i 2 . 7 V Case 2: Diode is OFF: v D v γ = 0 . 7 V and i D = 0. Then, from KVLs above, v o = v i - 10 3 i D = v i . To ±nd when the diode is OFF ( v D 0 . 7 V ): v D = v i - 2 v γ = 0 . 7 v i 2 . 7 V In sum, v 0 = 2 . 7 V for v i 2 . 7 V (diode ON) and v 0 = v i for v i 2 . 7 V (diode OFF). Note that this is a clipper circuit.
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09F-quiz-1-sol - ECE65 (Fall 2009), Quiz 1 Notes: 1. Write...

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