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Unformatted text preview: After doing so, and labeling the resistor currents, we have the circuit shown. Apply KCL at the top node of the current source to get Apply KVL to the outside loop to get So And so the power supplied by each source: Source Power delivered 8V voltage source 3V voltage source 3A current source 1.25A current source P3.61 P3.615 So the circuit is equivalent to Then P3.628 Replace the ammeter by the equivalent short circuit and label the current measured by the meter as i m . The 10Ω resistor at the right of the circuit is in parallel with the short circuit that replaced the ammeter so it’s voltage is zero as shown. Ohm’s law indicates that the current in that 10Ω resistor is also zero. Applying KCL at the top node of that 10Ω resistor shows that DP33...
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This note was uploaded on 04/15/2010 for the course ECE ece35 taught by Professor Xiejiang during the Winter '10 term at UCSD.
 Winter '10
 xiejiang
 Volt

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