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Unformatted text preview: After doing so, and labeling the resistor currents, we have the circuit shown. Apply KCL at the top node of the current source to get Apply KVL to the outside loop to get So And so the power supplied by each source: Source Power delivered 8V voltage source 3V voltage source 3A current source 1.25A current source P3.61 P3.615 So the circuit is equivalent to Then P3.628 Replace the ammeter by the equivalent short circuit and label the current measured by the meter as i m . The 10 resistor at the right of the circuit is in parallel with the short circuit that replaced the ammeter so its voltage is zero as shown. Ohms law indicates that the current in that 10 resistor is also zero. Applying KCL at the top node of that 10 resistor shows that DP33...
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 Winter '10
 xiejiang
 Volt

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