HW5solutions

# HW5solutions - Try then e.g. P6.5-6 Use the negative...

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ECE35 Win’09 Homework 5 Solutions Chapter 6: 6.3-1, 6.3-7, 6.4-4, 6.4-5, 6.4-6, 6.4-11, 6.4-17, 6.5-6 and begin Chapter 7: 7.2-13, 7.3-1 (no plot) P6.3-1 P6.3-7

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P6.4-4 Ohm’s law: KVL: P6.4-5
P6.4-6 KCL at node b: KCL at node a: So . P6.4-11 Node equations: and so with the given values:

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P6.4-17 Represent this circuit by node equations. and So We require

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Unformatted text preview: Try then e.g. P6.5-6 Use the negative resistance converter, entry ( h ) in Figure 6.6-1. P7.2-13 Well write and solve a node equation. Label the node voltages as shown. Apply KCL at node a to get so Then P7.3-1 Given The capacitor voltage is given by For In particular, For In particular, For Now the power and energy are calculated as and...
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## This note was uploaded on 04/15/2010 for the course ECE ece35 taught by Professor Xiejiang during the Winter '10 term at UCSD.

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HW5solutions - Try then e.g. P6.5-6 Use the negative...

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