ex5s09key - Quiz 5 CH 353 Sumer 2009 Vanden Bout 5 Name Kt...

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Unformatted text preview: Quiz 5 CH 353 Sumer 2009 Vanden Bout 5.. Name: Kt i Carefully read all the problems. The first page has potentially useful information. The last page is for extra writing space. R = 8.314J K‘l mol'1 R = 8.314x10'2 L bar K'l mol'l R = 8.206x10'2 L atm mol'l K'l latm = 1.01325 bar T/K = T/°C + 273.15 1atm—L = 101.325 J 1bar—L = 100 J 750 Torr = 1 bar 1 bar = 105 Pa dP AS AH ln£_—ARH” 1 1 dT AV_TAV K1 R 571 AH=fCPdT ARG=ARG°+RT1nQ ARG°=—RT1nK Please sign at the bottom to certify that you have worked on your own. I certify that I have worked the following exam without the help of others, and that the work I am turning in is my own. Signed: ------------------------------------------------------------ Signature Date l. True/False Circle either T or F for each statement (10 points each) @ F If ARH° > 0 then K increases with increasing temperature it 9,W&0-memi CG T 'x 5 qu dig“ 4: a F The activity of an ion in a 1 M solution is less than the concentration. #7,...— ——'— T ® The activity of an idealgis measured relative to the standard state of 1% if) F If ARG° > 0 at room temperature for the following reaction, then the partial pressure of oxygen at equilibrium is less than 1 bar. 2Fe203(s)—>4Fe(s) + 302(g) ‘4 5 (as: W A ('1 ® J film :6 Q F The equilibrium constant KP is independent of pressure. L. 2A. (25 points) Nitrogen and hydrogen gases reaction to form ammonia gas by the following reaction N2(g) + 3H2(g)——>2NH3(g) At 400°C a mixture of 3 moles of N2 ,0 5 moles of H2 and 0 045 moles of ammonia are found to b; @ in equilibrium in a 3 L container. What IS AR G° for this reaction? mot. , SSHS' pm, , (3 31.5)(0 ol3lLitmkawr) 55 IS 19‘1” , f L F92: fies—56% 1‘) 1 3L la?! J, 2 3:14)?— ; w 5in (g) @ (lmaafiz (flut/ )(flli/>J Fm : Olquflflaal): 0% bar F: f" 3.94 . \o L: [55x05 P0 9 l b“ ' if; 7 ; ‘flTLhL: “8.31H36‘wl'(97gk)fihk A(Gl° :: ‘l'LeLCl kSnM 28. For the following reaction N204(g)—>2N02(g) At a particular temperature you find the system is at equilibrium at a particular temperature when you have one mole of N204 and 0.1 moles of NO2 at a total pressure of 1 bar. At the same temperature you have a different mixture with 0.8 moles of N204 and 03 moles of NO2 at a total pressure of 0.1 bar. Is this second system ilibrium? (justify your answer mathematically) 1 L:— a @ aw“ Q i K , '2‘”l 5%ch “3+ .50 WW“ WM“ Wit/am“) @ W: \\rv0’( P [email protected] ‘ 0min“ PNzOq- VIA :— 0 Clo? P, Cd \DCUF 5N2?- "-"- PING” _—_-_ (DA/ltd 1' D 06105} Ejfllol’ '0 <2“ \ ':_ angiqa - = 03/” — C’ ' P3601 _ 2" 1 ‘ 'ijL ‘ F Y_; ( A?) 3 (LDCIOQ) 5 CLDOIMOS PM; ’(I). VKWXCRZ? 000:: ' 3A. CaC03(s)—>Ca0(5)+C02(8) 653 ARG° = 83.7 kJ mol‘1 Given that atmosphere has a partial pressure of 38 Pascal C02, if you have a chunk of-calcium carbonate at 25°C sitting out in the atmosphere, will it decompose to calcium oxide and carbon dioxide? Why or why not? DH}: -: .— @TL'VWK \C 1 (map ( ' AC’I/ if) “— fix? (”Si?(|®/C§-3l‘l(2®3> : K : 2.13 K to“3 0‘03?" 7— Pea; - $.qu M) -:’3.<8)k\t5L1 _ ‘. 5’; F631 lbcu" LEI/43 3B. Given the following plot of the temperature dependence of an equilbrium constant for a reaction. a H @ls this reaction exothermoic or endothermic? QXO—H/LLVM (— SLAVE: /£ @ What IS ARI-1° for this reaction? l33§r [7— : _,..r hat IS AR S° for this reaction? (5.35 H53" 3 “l H“ ) 15.5 a 15 : ammo -I 14.5 a}: U0 6M ‘4 in; ~ thunk: # 213.5 .1 -SI3[H(2‘N|0UZ): “251.33.; 2 0“. LAC"! 12.5 T 12 .___, wins: W 31539" 2.4%!‘ 11.5 11 3.3 3.4 3.5 3.6 3.7 3.8 3.9 4. (50 Points) H2(g) + 12(g)<-—>2H1(g) Data at 298 K AfH° (kl mol") S°(.l K’l mol") CP° (J K" mol") H2(g) 0 130.7 28 .8 12(g) 62.4 260.7 37.6 Hl(g) 26.50 206.6 29.2 You start with 1 mole pure HI and raised to a temperature of 600K at constant pressure of 1 bar. What are the partial pressures of H2 and 12 at equilibrium? (you can assume ARH° and ARS° are independent of temperature) What is AU in going from the initial state to equilibrium? “l le 8" SK- Ifiv—E @DTC1CLOOOK): .- w ._ W) (21030:?) : ,ng WOW) 0K?(32‘13(103>/C5’3M(000)])Claw H2 I?- HI W032; ‘ O D l l #— -2 .fx ‘l X -ZX D C .1 go’ Q9 X X l'ZX I Q} i ( ' W "‘1 “SW 7 x: 0.08%:0.084 .: to r. "’ 'A w F DU 1+ x (H + Aflt f ‘bar 3 L -' I 2 - I - ' L\ 03075? (“HO 0,8511% Oat; (“m/)0) 03‘0" [husk lx posthw. S VICE, rat/{m WA {‘5 draw/{55 . :- 0 .L 034%)” ' ...
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