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Unformatted text preview: lenoir (wml297) homework 06 Turner (58220) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Consider four vectors vector F 1 , vector F 2 , vector F 3 , and vector F 4 , where their magnitudes are F 1 = 36 N, F 2 = 35 N, F 3 = 20 N, and F 4 = 57 N. Let 1 = 130 , 2 = 150 , 3 = 34 , and 4 = 56 , measured from the positive x axis with the counterclockwise angular direction as positive. What is the magnitude of the resultant vec tor vector F , where vector F = vector F 1 + vector F 2 + vector F 3 + vector F 4 ? Correct answer: 26 . 4696 N. Explanation: Basic Concepts: Vector components fig ure1 Solution: The x components of the forces vector F 1 , vector F 2 , and vector F 3 are F 1 x = F 1 cos(130 ) = 23 . 1404 N F 2 x = F 2 cos( 150 ) = 30 . 3109 N F 3 x = F 3 cos(34 ) = 16 . 5807 N F 4 x = F 4 cos( 56 ) = 31 . 874 N . and the y components are F 1 y = F 1 sin(130 ) = 27 . 5776 N F 2 y = F 2 sin( 150 ) = 17 . 5 N F 3 y = F 3 sin(34 ) = 11 . 1839 N F 4 y = F 4 sin( 56 ) = 47 . 2552 N . The x and y components of the resultant vec tor vector F are F x = F 1 x + F 2 x + F 3 x + F 4 x = ( 23 . 1404 N) + ( 30 . 3109 N) + (16 . 5807 N) + (31 . 874 N) = 4 . 99657 N F y = F 1 y + F 2 y + F 3 y + F 4 y = (27 . 5776 N) + ( 17 . 5 N) + (11 . 1839 N) + ( 47 . 2552 N) = 25 . 9937 N Hence the magnitude of the resultant vector bardbl vector F bardbl is bardbl vector F bardbl = radicalBig F 2 x + F 2 y = radicalBig ( 4 . 99657 N) 2 + ( 25 . 9937 N) 2 = 26 . 4696 N 002 (part 2 of 2) 10.0 points What is the direction of this resultant vector vector F ?...
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This note was uploaded on 04/15/2010 for the course PHY 12343 taught by Professor Turner during the Spring '10 term at University of Texas at Austin.
 Spring '10
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