Quiz6Solution - CE 3700 Fluid Mechanics Homework Quiz 6...

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Unformatted text preview: CE 3700 Fluid Mechanics Homework Quiz 6 10/21/05 Name: SUIE H ov\ SHOW ALL UNITS Velocity ofthe waterjet = 18 m/S Weight of the tank plus water at the instant shown = 100 N Water temperature : 10°C Step I a) Find the force acting on the stop block. block I _ m . b) Find the force acting on the floor that supports the tank. , ‘ as. 1. Diameter of the water jet 2 0.03 m f: a) 212% 2 615(0)} 2 anM—u) EL , F54? 2 <in0% x‘Ti-g)<_g.lg@<15%>[l£(c.umjfl(—9 1‘ + 73.4- N 5+b‘7‘o‘oct Adina ow hmk : 78:4 N a hm: Ltd-mt on Shflujk : H +— ED) E7; : : €T%VA<_{) Lei M : firm «F “cor 110(1ij ow 41mk w : M130 cg Jmmk Vim; wider mst thk m7. 2: 60905:} X \l g ><_ léiq("§~><1gfig>[%<o,ozflfl(.l> 4— [00 N : 2&5 N + loo N = 36 N N"\l\{ ': N “fftij‘fi : ’3ng T ow Hue r ’- ‘41ka ach’wj _ glgN ll Flanges 2. Water flows through the horizontal nozzle and discharges to the atmosphere. ' D1= 0.25 P: V]: 3.500 fi/s D3 = 010 ft V; = 21.875 ft/s - Water temperature = 50°F Find the force (magnitude and direction) that the nozzle exerts an the bolts in the flange. jig—t * ?;(""r E : 1?}. Jr E '1‘ 1j r 2" 23 Ll__ '7- L4 I L- 1604347— 1%: M75") = @2453) Ma.) 2(221 £51) “@A. + PW : (Q(W&L—1fi<.) ': O.l72s‘?"3 “9941' __ _ slu S ‘ T “3 {It 45;. Team — (M4113 X 1 51u3><0.\71?)<21'815 5 ‘3500 ?) ~ @Elfl[§<oestgj L——‘—_—V‘——“‘_JL———~—W 5.1 M 22.21% : —1¢.\ M r6) 0? ioul‘rr atfiiA an HBZZ‘e : {H gum: 0? made cud-m3 w ‘ootfi 7- 1(oa\ “7? ‘3 CE 3700 Fluid Mechanics Homework Quiz 6 10/21/05 Name: g 0 Eu“ 0 Y‘- SHOW ALL UNITS 1. Diameter of the water jet : 0.02 m 1‘ Velocity of the water jet = 16 m/s _ LIX Weight of the tank plus water at the instant shown : 200 N Water temperature = 10°C :2) Find the force acting 0n the stop block. 131061: b) Find the force acting on the floor that supports the tank. 5+0? Mud: adran on hmk : 17‘ ‘3 N ‘_> 0) 2F 2 :‘QWIQVAQ—t) Lai- N —: hug 01“ “nor Ltd-TM? on fink W = wakflht cc hunk wtng waJ—er msxda “Hank N - W = WE WAG!) ‘igL ,. w T‘— 7— N 7.. Q000%3x \mX-1‘3-04‘M;XIG ‘5‘)[ I(0.bz_m3] (*1) + 200 N ’1 73,6914 1— LooN = Z’TGN 1 +714 iflfittj : 27M) 1‘ +uvxk “Haj : 1WD N a on Hoof 2. Water flows through the horizontal nozzle and discharges to the atmosphere. D: 0.40 ft V] = 2.500 ft/s D3 : 0.12 ft V3 2 27.778 ft/s Water temperature = 50°F , Find the force (magnitude and direction) that the nozzle exerts an the bolts in the flange. L Fmd pressuve‘afi G Mm germ-NW E3. v?( Vl'l.‘ 2- ‘L —- t .__ ._. 1. Y 21 4- l3 _. 4* E17 + ,ia— EL: 9 .“2'_'. W7- 1)‘ : Y( Vlzavt :QZA'EC‘?) (21778 @300 5) 2.[ 32.7. PJr/sz) Force. a? bum och-mg. on milk 2 77.8 M 74—.— fira. o? nolzla add-“3 on boH’S : —+ CE 3700 Fluid Mechanics Homework Quiz 6 10/21/05 Name: 30 ‘M Jr; “A SHOW ALL UNITS 1. Diameter of the water jet = 0.04 In Velocity ofthe waterjet : 24 m/s Weight of the tank and water at the instant shown : 300 N Water temperature = 10°C a) Find the force acting on the stop block. b) Find the force acting on the floor that supports the tank. m3 i k = + 24% N “t W L - ch’Fn Ema "" Z45“ a fix K TAM:- aC'kV‘j : 4:- oh Sh)? block b) if: 2 QTY; V' L91 N7— hru 0’? Hear adrinj 0h MAME W - WeighJr 0‘: mela anal waJ—er instdie hunk >11 : QUE VAC“) N P w : Q 1”} T) A (-L‘) N : (WOO :33 K —L?.SS (0.04mffC—t) + 300 N :2 (080 N L 300 N 2 ago N ngwfiififi : ago N T TO “\g (LLin : figo N L On Qlcov 2‘ Water flows through the nozzle and discharges to the atmosphere. D1: 0.50 ft V1: 3.000 ft/s D2 2 0.15 ft V; = 33.333 fi/s Water temperature = 50°F Find the force (magnitude and direction) that the nozzle exerts on the bolts in the flange. 1. Ft"an prcsmrt q’r CD ’FVDM gem/mum Ex. $34k; = 1*? 2(311 , 7—; 7— L pr 7. fl = \O/ (VLLEV. > = (6&4?!) (33.333‘EZ) —C3,o/5) 1‘1 = BL 1063 W 2. FM& Puree. achxj on both Jon—ma Momentum E3" M1 37“ _, M Lg— “? I L EJOHS —‘ Q34 Hg X lsluj 0.5—8? ‘5' ‘ .I ,Q . W4 Mffiu— w ' 3M" M 201.70 M = — \76 Mr Fon 0? lob”: “1W3” Mute 5 HEM ‘— Fuvcp. if no‘lz‘t : Hg we a 00H“? Uh \oolfi ...
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Quiz6Solution - CE 3700 Fluid Mechanics Homework Quiz 6...

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