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Unformatted text preview: h = 1.0000 2.2470 2.8019 2.2470 1.0000 Therefore H(z) = 1 + 2.24 z-1 + 2.80z-2 +2.24 z-3 + z-4 1 EEL 3135: Signals and Systems Dr. Fred J. Taylor, Professor The filter response and pole zero distribution are shown below. Figure 1: Magnitude frequency response (two-sided) and pole zero distribution. The heuristic 5 th order filter has a symmetric impulse response and is therefore linear. According to theory the group delay is τ =(N-1)/2 = 2 samples. The theoretical linear phase response is θ ( ω )=-τω + φ . The phase response is computed as shown below. >> [h,w]=freqz(h,1); >> h=[1, 2.24, 2.8, 2.24, 1]; >> [h,w]=freqz(h,1); >> plot(180*angle(h)/pi); >> plot(w,180*angle(h)/pi); and graphically interpreted in Figure 2. The estimate slope is m=-2 which agrees with the theoretical predication. Figure 2: Phase response 2 Passband Passband π/2 π Slope m=-2...
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This note was uploaded on 04/15/2010 for the course EEL 3135 taught by Professor ? during the Spring '08 term at University of Florida.
- Spring '08