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Challenge_16-1

# Challenge_16-1 - ω that set the term H(e j ω)= 1 e-j11 ω...

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Discrete-Time Signals and Systems Dr. Fred J. Taylor, Professor Lesson Title: FIR Frequency Response Lesson Number: 16 (Section 6-5 to 6-6) L Challenge An N=12 order comb filter has an impulse response h[k]={1,0,0,0,0,0,0,0,0,0,0,1} and is clocked at a rate of f s =1MHz. Where are the filter’s null frequencies located? Response The FIR’s frequency response is given by: H(e j ω )= e j0 ω + e -j11 ω = 1 + e -j11 ω The zeros correspond to those frequencies
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Unformatted text preview: ω that set the term H(e j ω )= 1 + e-j11 ω to zero. The positive baseband frequencies are ω = { π /11, 3 π /11, 5 π /11, 7 π /11, 9 π /11, 11 π /11} or frequencies of f = {1/22, 3/22, 5/22, 7/22, 9/22, 11/22}f s . Simulation: >> h= [1 0 0 0 0 0 0 0 0 0 0 1 zeros(1,1000)]; >> freqz(h,1) Frequency response (dB gain – top, phase response – bottom) 1 1/11 11/11 3/11 5/11 7/11 9/11...
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