solution_pdfhg - Patel(sap785 – Homework#4 – shubeita...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Patel (sap785) – Homework #4 – shubeita – (58645) 1 This print-out should have 5 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the student to overcome gravity is most nearly 1. P = 875 W. 2. P = 5 , 600 W. 3. P = 1 . 1 W. 4. P = 87 . 5 W. 5. P = 560 W. correct Explanation: P = W t = F d t = (700 N) (8 m) 10 s = 560 W . 002 10.0 points A force vector F ( x, t ) = ˆ ı b t x acts on an object, where b is the constant 10 N / m · s. When the object is at x = 5 m at t = 2 sec, its velocity v = ˆ ı (4 m / s) +ˆ (10 m / s). At this moment, what power is being deliv- ered by the force? 1. 100 Watts 2. 10 Watts 3. 300 Watts 4. 400 Watts correct 5. 800 Watts 6. 50 Watts 7. Zero because the object’s velocity is in- stantaneously constant....
View Full Document

This note was uploaded on 04/16/2010 for the course PHY 317k taught by Professor Kopp during the Spring '07 term at University of Texas.

Page1 / 2

solution_pdfhg - Patel(sap785 – Homework#4 – shubeita...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online