solution_pdfvbf - Patel (sap785) homework #10 shubeita...

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Patel (sap785) – homework #10 – shubeita – (58645) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 36 . 8 vibrations in 29 s. Also, a given maximum travels 442 cm along the rope in 8 . 3 s. What is the wavelength? Correct answer: 41 . 9657 cm. Explanation: Let : n = 36 . 8 vibrations , t 1 = 29 s , Δ x = 442 cm , and t 2 = 8 . 3 s . The speed oF the wave is v = Δ x t 2 and the Frequency is f = n t 1 or T = t 1 n , so λ = v f = v 1 f = v T = Δ x t 2 t 1 n = (442 cm) (29 s) (8 . 3 s) (36 . 8) = 41 . 9657 cm . keywords: 002 10.0 points A horizontal string can transmit a maximum power oF P (without breaking) iF a wave with amplitude A and angular Frequency ω is trav- eling along it. In order to increase this max- imum power, a student Folds the string and uses this ‘double string’ as a transmitter. Determine the maximum power
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This note was uploaded on 04/16/2010 for the course PHY 317k taught by Professor Kopp during the Spring '07 term at University of Texas.

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solution_pdfvbf - Patel (sap785) homework #10 shubeita...

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