Unformatted text preview: Solution: (a) E ( X ) = Z ∞∞ xf ( x ) dx = Z 1 x 4 x 3 dx = Z 1 4 x 4 dx = 4 5 x 5  1 = 4 5 (b) ±or the median x , . 5 = P ( X ≤ x ) = Z x f ( x ) dx = Z x 4 x 3 dx = x 4  x = x 4 Solve for x , x = 0 . 5 1 / 4 = 0 . 84 1...
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 Spring '08
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 Probability, dx, discrete random variable

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