# HW 2 - Yes Why? Because -3.47 is< than -2.024 at the .05...

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Homework 2 Due date: 02/01/2010, 10:00 PM EST Maximum points: 10 1. (5 points) Suppose that we are testing H 0 : µ = µ 0 versus H 1 : µ µ 0 . Calculate the P -value for the following observed values of the test statistic: Given Calculations P-Value (a, Z 0 = 2.25 2(1- .98778) = 0.02444 (b) Z 0 = 1.55 2(1-.93943) = 0.12114 (c) Z 0 = 2.10 2(1-0.98214) = 0.03572 (d) Z 0 = 1.95 2(1-0.97441) = 0.05118 (e) Z 0 = -0.10 2(1- .5398) = 0.9204 2. (5 points) Consider the Minitab output shown below. Two-Sample T-Test and CI: Y1, Y2 Two-sample T for Y1 vs Y2 N Mean Std. Dev. SE Mean Y1 20 50.19 1.71 0.38 Y2 20 52.52 2.48 0.55 Difference = mu (X1) – mu (X2) Estimate for difference: -2.33341 95% CI for difference: (-3.69547, -0.97135) T-Test of difference = 0 (vs not = ) : T-Value = -3.47 P-Value = 0.001 DF = 38 Both use Pooled Std. Dev. = 2.1277 (a) Can the null hypothesis be rejected at the 0.05 level?

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Unformatted text preview: Yes Why? Because -3.47 is< than -2.024 at the .05 level (b) Is this a one-sided or two-sided test? Two-sided test (c) If the hypothesis had been H : µ 1- µ 2 = 2 versus H 1 : µ 1- µ 2 ≠ 2 would you reject the null hypothesis at the 0.05 level? Yes, I would reject the null hypothesis because the p-value is at .001 which is less than .05 (d) If the hypothesis had been H : µ 1- µ 2 = 2 versus H 1 : µ 1- µ 2 < 2 would you reject the null hypothesis at the 0.05 level? Can you answer this question without doing any additional calculations? Why? Yes, I would reject the null hypothesis. I would have to redo the T distribution since now I have a left tailed alternative hypothesis. .....
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## This note was uploaded on 04/16/2010 for the course IET 19575 taught by Professor Dr.joshi during the Spring '10 term at Morehead State.

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HW 2 - Yes Why? Because -3.47 is< than -2.024 at the .05...

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