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Mathcad - Homework #4 Part 2 Solution 2009

Mathcad - Homework #4 Part 2 Solution 2009 - PRESTRESSED...

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PRESTRESSED CONCRETE DESIGN CE486/586 - Homework #4 Solution 1.) 28IT40 Strain Compatability 28IT40 Section Properties - PCI Design Handbook Page 2-45 A IT 736in 2 := I IT 93503 in 4 := y b 15.83in := h IT 40in := b IT 12in := w IT 767plf := S t 3869in 3 := S b 5907in 3 := L IT 34ft := M w x , ( ) w x 2 L IT x ( ) := 198-S Strand Pattern A ps 19 0.153 in 2 := A ps 2.907 in 2 = y s 4.21in := d p h IT y s := d p 35.79 in = f pu 270ksi := f pj 75% f pu := f pj 202.50 ksi = TL 38ksi := f pe f pj TL := f pe 164.50 ksi = E p 28500ksi := ε pe f pe E p := ε pe 0.005772 = P e f pe A ps := P e 478.20 kip = e y b y s := e 11.62 in = Superimposed dead load w SDL 2800plf := Homework #4 Part 2 Solution 2009.xmcd Page 1
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