Mathcad - Homework #4 Part 2 Solution 2009

Mathcad - Homework #4 Part 2 Solution 2009 - PRESTRESSED...

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PRESTRESSED CONCRETE DESIGN CE486/586 - Homework #4 Solution 1.) 28IT40 Strain Compatability 28IT40 Section Properties - PCI Design Handbook Page 2-45 A IT 736in 2 := I IT 93503 in 4 := y b 15.83in := h IT 40in := b IT 12in := w IT 767plf := S t 3869in 3 := S b 5907in 3 := L IT 34ft := Mwx , () wx 2 L IT x := 198-S Strand Pattern A ps 19 0.153 in 2 := A ps 2.907 in 2 = y s 4.21in := d p h IT y s := d p 35.79 in = f pu 270ksi := f pj 75% f pu := f pj 202.50 ksi = TL 38ksi := f pe f pj TL := f pe 164.50 ksi = E p 28500ksi := ε pe f pe E p := ε pe 0.005772 = P e f pe A ps := P e 478.20 kip = ey b y s := e 11.62 in = Superimposed dead load w SDL 2800plf := Homework #4 Part 2 Solution 2009.xmcd Page 1
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Determine concrete stress at the top and bottom fibers and at the location of the prestressing. M ITandSDL Mw IT w SDL + 0.5 L IT , () := M ITandSDL 515.43 kip ft = M ITandSDL 6185.18 in kip = f t P e 1 A IT e S t M ITandSDL S t + := f t 812 psi = f b P e 1 A IT e S b + M ITandSDL S b := f b 543 psi = f atPS P e 1 A IT e 2 I IT + M ITandSDL e I IT := f atPS 572 psi = f'
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This note was uploaded on 04/17/2010 for the course ECE 112 taught by Professor Traylor during the Winter '09 term at Oregon State.

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Mathcad - Homework #4 Part 2 Solution 2009 - PRESTRESSED...

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