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Mathcad - Homework #6 2010 Solution

# Mathcad - Homework #6 2010 Solution - PRESTRESSED CONCRETE...

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PRESTRESSED CONCRETE DESIGN CE486/586 - Homework #6 Solution Units SECTION & SPAN GEOMETRY A 46.91 in 2 := y b 6.81in := I 1048 in 4 := Q 99.85 in 3 := b w 2in := w 150 pcf A := w 49 plf = h 14in := L oo 15 ft := L cc 14ft := L oh 6in := W t w L oo := W t 733 lbf = PRESTRESSING A ps 7 0.085 in 2 := A ps 0.595 in 2 = d b 0.375in := y e 1 1.75in 2 13 16 in + 3 1.75 in 13 16 in + + 3 13 16 in + 7 := y e 2.06 in = y c 4 3 8 in 13 16 in + 3 13 16 in + 7 := y c 1.03 in = y x ( ) y e y e y c ( ) 2 L oo x L oh + ( ) := e x ( ) y b y x ( ) := y 0in ( ) 1.99 in = y L cc 2 1.03 in = d x ( ) h y x ( ) := 0.8 h 11.20 in = d actual controls full length of beam. f pu 270ksi := f pj 75% f pu := f pj 203 ksi = TL 35 ksi := f pe f pj TL := f pe 168 ksi = L t f pe 3 1 ksi d b := L t 20.94 in = Lt = transfer length from end of beam. Homework #6 2010 Solution.xmcd 2/24/2010 Page 1

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