Mathcad - Homework #6 2010 Solution

Mathcad - Homework #6 2010 Solution - PRESTRESSED CONCRETE...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PRESTRESSED CONCRETE DESIGN CE486/586 - Homework #6 Solution Units SECTION & SPAN GEOMETRY A 46.91 in 2 := y b 6.81in := I 1048 in 4 := Q 99.85 in 3 := b w 2in := w 150 pcf A := w 49 plf = h1 4 i n := L oo 15 ft := L cc 14ft := L oh 6in := W t wL oo := W t 733 lbf = PRESTRESSING A ps 7 0.085 in 2 := A ps 0.595 in 2 = d b 0.375in := y e 1 1.75in 2 13 16 in + 3 1.75 in 13 16 in + + 3 13 16 in + 7 := y e 2.06 in = y c 4 3 8 in 13 16 in + 3 13 16 in + 7 := y c 1.03 in = yx () y e y e y c 2 L oo xL oh + := ex y b := y0 in ( ) 1.99 in = y L cc 2 1.03 in = dx h yx := 0.8 h 11.20 in = d actual controls full length of beam. f pu 270ksi := f pj 75% f pu := f pj 203 ksi = TL 35 ksi := f pe f pj TL := f pe 168 ksi = L t f pe 3 1 ksi d b := L t 20.94 in = Lt = transfer length from end of beam. Homework #6 2010 Solution.xmcd 2/24/2010 Page 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
P e x () A ps f pe xL oh + L t oh + L t if A ps f pe otherwise := P e L cc 2 99.7 kip = x input 91 22 43 64 86 07 28 4 i n := The first point, 9", equals h/2 from face of support. Part 1. - Vcw Elastic f' c 12000psi := f sp 4f ' c psi := f sp 438 psi = f pc x P e x A := V p x P e x () y e y c 2 L oo := V p L oo 2 1.15 kip = V cw_Elastic x Ib w Q f sp f pc x 2 +
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 7

Mathcad - Homework #6 2010 Solution - PRESTRESSED CONCRETE...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online