PRESTRESSED CONCRETE DESIGN
CE486/586 - Homework #6 Solution
Units
SECTION & SPAN GEOMETRY
A
46.91 in
2
⋅
:=
y
b
6.81in
:=
I
1048 in
4
⋅
:=
Q
99.85 in
3
⋅
:=
b
w
2in
:=
w
150 pcf
⋅
A
⋅
:=
w
49 plf
=
h
14in
:=
L
oo
15 ft
⋅
:=
L
cc
14ft
:=
L
oh
6in
:=
W
t
w L
oo
⋅
:=
W
t
733 lbf
=
PRESTRESSING
A
ps
7 0.085
⋅
in
2
⋅
:=
A
ps
0.595 in
2
=
d
b
0.375in
:=
y
e
1
1.75in 2
⋅
13
16
in
⋅
+
⎛
⎜
⎝
⎞
⎟
⎠
⋅
3
1.75 in
⋅
13
16
in
⋅
+
⎛
⎜
⎝
⎞
⎟
⎠
⋅
+
3
13
16
⋅
in
⋅
+
7
:=
y
e
2.06 in
=
y
c
4
3
8
in
⋅
13
16
in
⋅
+
⎛
⎜
⎝
⎞
⎟
⎠
⋅
3
13
16
⋅
in
⋅
+
7
:=
y
c
1.03 in
=
y x
( )
y
e
y
e
y
c
−
(
)
2
L
oo
⋅
x
L
oh
+
(
)
⋅
−
:=
e x
( )
y
b
y x
( )
−
:=
y 0in
(
)
1.99 in
=
y
L
cc
2
⎛
⎜
⎝
⎞
⎟
⎠
1.03 in
=
d x
( )
h
y x
( )
−
:=
0.8 h
⋅
11.20 in
=
d actual controls full length of beam.
f
pu
270ksi
:=
f
pj
75% f
pu
⋅
:=
f
pj
203 ksi
=
TL
35 ksi
⋅
:=
f
pe
f
pj
TL
−
:=
f
pe
168 ksi
=
L
t
f
pe
3
1
ksi
⋅
d
b
⋅
:=
L
t
20.94 in
=
Lt = transfer length from end of beam.
Homework #6 2010 Solution.xmcd
2/24/2010
Page 1

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