Mathcad - Homework #7 2010 Solution

# Mathcad - Homework #7 2010 Solution - PRESTRESSED CONCRETE...

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PRESTRESSED CONCRETE DESIGN CE486/586 - Homework #7 Solution Units CONCRETE f' ci 5400 psi := f' c 7000psi := f' c_slab 5000psi := E c 57000 f' c psi := E c 4769 ksi = E c_slab 57000 f' c_slab psi := E c_slab 4031 ksi = n E c_slab E c := n 0.845 = SPAN GEOMETRY & SECTION PROPERTIES L oo 57ft 10 in + := L oo 57.83 ft = L cc 57ft := L oh 5in := S g 25ft := b1 1 i n := h3 1 i n := A 286in 2 := y b 13.27in := b w := b v b := b v 11.00 in = I 29660in 4 := S b I y b := S b 2235 in 3 = t slab 5.5in := b struct min S g 28 t slab b v + , L cc 4 , := b struct 99.0 in = See ACI 8.10.2 b eff nb struct := b eff 83.67 in = Composite Section Properties, See EXCEL y bc 25.90in := I c 104790 in 4 := S bc 4046 in 3 := Homework #7 2010 Solution.xmcd Page 1

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PRESTRESSING f pu 270ksi := f pj 75% f pu := f pj 202.5 ksi = TL 40.0ksi := f pe f pj TL := f pe 162.50 ksi = A ps 18 0.153 in 2 := A ps 2.754 in 2 = y e 12.00in := y c 4.50in := P e A ps f pe := P e 448 kip = y p x () y e y e y c L oo 2 xL oh + := y p L oh 12.00 in = y p L cc 2 4.50 in = e p x y b y p x := LOADING w bm 150 pcf A := w bm 298 plf = w slab 150 pcf t slab S g := w slab 1719 plf = S g 25.00 ft = w ll 50psf S g := w ll 1250 plf = w u 1.2 w bm w slab + 1.6 w ll + := w u 4420 plf = Vwx , w L cc 2 x := Mwx , wx 2 L cc x := Homework #7 2010 Solution.xmcd Page 2
Part 3, Vertical Shear Strength at 0.25L h c ht slab + := h c 36.5 in = 0.8 h c 29.20 in = y p 0.25 L cc () 8.20 in = d p h c y p 0.25 L cc := d p 28.30 in = d max d p 0.8 h c , := d 29.20 in = V d Vw bm w slab + 0.25 L cc , := V d 28.7 kip = V i V 1.6 w ll 0.25L cc , := V i 28.50 kip = M max M 1.6 w ll 0.25 L

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## This note was uploaded on 04/17/2010 for the course ECE 112 taught by Professor Traylor during the Winter '09 term at Oregon State.

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Mathcad - Homework #7 2010 Solution - PRESTRESSED CONCRETE...

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