Homework 2 - October 9, 2009 Biology 1223 Dr. R. Gardiner...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
October 9, 2009 Biology 1223 Dr. R. Gardiner HOMEWORK ASSIGNMENT TWO Genes Chromosomes and Human Genetics (Name of Homework for clickers HW02) 1. A man with haemophilia ( a recessive, sex-linked condition) has a daughter of normal phenotype. She marries a man who is normal for the trait. What is the probability that a daughter of this mating will be a haemophiliac? A. 100 % B. 75 % C. 50 % D. 25 % E. 0 2. From question 1 that a son from this mating will be a haemophiliac? A. 100 % B. 75 % C. 50 % D. 25 % E. 0 3, A wild-type fruit fly (heterozygous for gray body colour and normal wings) is mated with a black fly with vestigial wing. The offspring have the following phenotype distribution: wild type, 778, black-vestigial 785, black-normal 158, gray-vestigial 162. What is the recombination frequency? A. 100 % B. 50 % C. 17 % D. 8 % E. 1 %
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
October 9, 2009 Biology 1223 Dr. R. Gardiner 4. Determine the sequence of genes along a chromosome based on the following recombination frequencies . A – B
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 4

Homework 2 - October 9, 2009 Biology 1223 Dr. R. Gardiner...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online