final review

final review - ENGR 2301 Nam e: -W 728 Mew There are a...

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Unformatted text preview: ENGR 2301 Nam e: -W 728 Mew There are a total 01100 points on the exam. Each of the five problems is worth 20 points. Show all of your work (diagrams, equnfions, calculations, em). Report each answer'with the correct units. Date: 1.) Determine the spring constant, k, for equilibrium of this system. Neglect the thickness of the beams. ‘ - o Each beam has 501M301? mass, \ Fflcflbnflass sal'ficq 2407; Sim/Ina has unsirefC/Ieafl @7355 of 0500M” §=é00 \ (wwmflfl 7‘ A”? ’2 $7 9 FE; 3w 7%? m ¢ ______J;__ PM”! 1‘ 7%” efiu'z/t'brium X z /WCOS(9 +/m (033* "3 Zmragfi 52‘ Zia/MI} Q 36 ‘ (“5% : 0,-5n7 sin g i "'T ks ——-— kOm 17.5mm.) 15-9”: camcosfa 56 _137— 3 Km 5:319 Sol :0 : “F5 3K — 2(50éjmgmgz) g- W—(mm ) 84“}?- - O ‘5 ”k({m -0.50c1m3(’2rn SInQ ’(qfiWJCOI‘Z—‘m cosaggi ’/000N(/'m Case/9g) I O 3 +1<(/[00 m2) 51m €00 -— 490.5 N-MCoséédé/aoo/UW 50540 2.) Determine the minimum force, P, for impending motion. Describe the" nature of the motion. Neglect the thickness of the beam. Neglect the size and mass of the wedge. [5mm is 50/43 “m mass _ ~ 1 F 'l P r‘ ‘ *nge i ' Wedge cui’JWPewoimg mO'l‘Ld‘a-x. Bean‘ag‘ra‘iuma xi Fe =24; M3 = 0.300% ZMA30 * @01L9)(‘ir81%5C1-.00g§ 4. (NB msgoakzm m3 ‘ + 0.300 N3C§fl ZOD)(2.00,,;) 3—,0 . Mg 5 2353 N CI’UZCIL 1L0 “3.6L [:4 fi/Offi N24 fl * gassme‘mw + @.9003C235.3N<—03 20”) “L a m floothlfiN)?’ 49W / Fa :r "ILL! {\i Two identical bars are connected with a fr the floor with a smoeth frictionless pin at frictionless roller at C, and a spring. The Spring is uncompressed when theta, 9, is equal to 90“. The system is allowed to come to equilibrium (spring under compression). ictionless pin at B. Bar AB is pinned to A. Bar BC is connected to both :1 Determine the angle theta, B, for equilibrium. __......____.—..*W.s. ){5 :7 2 (ZflOm) 005 5’} 5,74,: : ~ 900m '5!th 50!: 26,50,437 i’a‘bé’ $69(29’7,2N)’ I: (é,00m51}79}5[) :0 74/,é/Wos 9 g 400 I"; Sin (‘9 74/.(9N 3"" €9.00 ffng d F; .: kxé = (/OO(2:)(3.00n1>COS :9 :_ (900 N 00:53 7419.5le fiéoo )(eoom‘was'a § ; m?" S {1“ t9 wig—éf Two identical bars are connected with a frictionless pin at B. Bar AB is pinned to the floor with a smooth frictionless pin ntA. Bar BC is connected to both a frictionless roller at C, and a spring. The spring is uncompressed when theta, 9, is equal to 90". The system is allowed to come to equilibrium (spring under compression). Determine the angle theta, B, for equilibrium. EN GR 23 01 - No me: Exam 3 Date: a 10!] points total oil-exam. a Work on blank sheets provided with exam. a Show your work to receive full. creclit (free-body—diagram, equations, calculations, etc.) ' '0 Show proper units with your calculations end on your fingil answers. 9 Attempt ever}r problem. 0 Clearly box or underline your fiu :1] answers. (30 points) The following is a cross-section of weather stripping for a storm door. The circular region in the cenier is void space (a hole). The bottom center of the object is the origin (3: and y axes shoWn). :1.) Determine the moment of inertia about the X axis shown. (15 points) h.) Determine the moment of inertia shoot the y axis showu. (15 points) . RLES mm u 35m 33 + foogafififioavi “Ema 3395an I 33% Espvm$80fvmw in +9 a l Ea .1... NWOL Ei ENGR 23 01 - Nome: Exam 3 Date: 100 points total on exam. a Work on blank sheets provided with exam. «- Show your work to receive full- credit (fiee—body—diagram, equations, calculations, etc.) ' ‘0 Show proper units with your calculations and on your fingl answers. a Attempt every problem. _ 9 Clearly box or underline your final answers. (36 points) The following is a cross-section of weather shipping for a storm door. The circular region in the center is void space (a hole). The bottom center of the object is the origin (3: and y axes shown). a.) Determine the'moment of inertia about thex axis shown. (15 points) 1).) Determine the moment of inertia alient the y axis shown. (15 points) I R135 mm 3.50 mm REED mm I . 4.) A lightweight umbrella design was have the following cross-section. Determine the centroid of cross-section. Determine the moment of inertia about a horizontal axis-throu h the centroid of the ' cross-section (that is, an x' axis). 13,: ‘ ‘ ‘ - . ' t W ._c-- ‘31 I . 4.) A lightweight umbrella design was proposed. The support arms for the umbrella ‘ have the following cross-section. Determine the centroid of cross—section. Determine the moment of inertia about a horizontal axis through the centroid of the ‘ cross-section (that is, an x' axis). Notethat the x' axis is NOT shown in the diagram below. ‘ “MM—Wm“ ...
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This note was uploaded on 04/18/2010 for the course ENGR 2312 taught by Professor Pressly during the Fall '09 term at Northwest.

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final review - ENGR 2301 Nam e: -W 728 Mew There are a...

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