Homework9-F08

Homework9-F08 - Homework 9 Chapt. 14 solutions (1) Cosine...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Homework 9 Chapt. 14 solutions (1) Cosine Wave The graph shows the position of an oscillating object as a function of time . The equation of the graph is , Part A What is A in the equation? Part B What is in the equation? Part C What is in the equation? From the figure we see when t = -N, x = M Using the cos wave function M = M cos(2 /T * (-N) + ) cos(2 /T * (-N) + )=1 (2 /T * (-N) + ) = 0, = 2 N /T 14.14. Model: The oscillating mass is in simple harmonic motion. Solve: (a) The amplitude A = 2.0 cm. (b) The period is calculated as follows: 2 2 10 rad s 0.628 s 10 rad s T T = = = = (c) The spring constant is calculated as follows: ( ) ( ) 2 2 0.050 kg 10 rad s 5.0 N m k k m m = = = = (d) The phase constant 1 4 rad. = - (e) The initial conditions are obtained from the equations ( ) ( ) ( ) ( ) ( ) ( ) 1 1 4 4 2.0 cm cos 10 and 20.0 cm s sin 10 x x t t v t t =- = -- At t = 0 s, these equations become ( ) ( ) ( ) ( ) 1 1 4 4 2.0 cm cos 1.414 cm and 20.0 cm s sin 14.14 cm s x x v =- = = -- = In other words, the mass is at + 1.414 cm and moving to the right with a velocity of 14.14 cm/s. (f) The maximum speed is ( ) ( ) max 2.0 cm 10 rad s 20.0 cm s v A = = = . (g) The total energy ( )( ) 2 2 3 1 1 2 2 5.0 N m 0.02 m 1.0 10 J E kA- = = = ....
View Full Document

Page1 / 4

Homework9-F08 - Homework 9 Chapt. 14 solutions (1) Cosine...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online