Homework11-help - 20.12. Model: The wave is a traveling...

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20.12. Model: The wave is a traveling wave. Solve: (a) A comparison of the wave equation with Equation 20.14 yields: A = 3.5 cm, k = 2.7 rad/m, ω = 124 rad/s, and . The frequency is 0 0 rad φ = 124 rad/s 19.7 Hz 22 f ππ == = b) The wavelength is: 2.33 m 2.7 rad/m k λ = (c) The wave speed 45.9 m/s vf . 20.16 Visualize: Please refer to Figure Ex20.16. Solve: The amplitude of the wave is the maximum displacement which is 6.0 cm. The period of the wave is 0.60 s, so the frequency 1 1 0.60 s 1.67 Hz fT = . The wavelength is 2 m/s 1.2 m 1.667 Hz v f = 20.25. Solve: (a) The frequency is air 343 m/s 1715 Hz 0.20 m v f = (b) The frequency is 8 9 3.0 10 m/s 1.50 10 Hz 1.50 GHz 0.20 m c f × = × = (c) The speed of a sound wave in water is v water = 1480 m/s. The wavelength of the sound wave would be 7 water 9 1480 m/s 9.87 10 m 987 nm 1.50 v f =× = × 20.26. Model: Light is an electromagnetic wave that travels with a speed of 3 × 10 8 m/s. Solve: (a) The frequency of the blue light is 8 14 blue 9 3.0 6.67 10 Hz 450 10 m c f × = × × (b) The frequency of the red light is 8 14 red 9 3.0 4.62 10 Hz 650 10 m f × × × (c) Using Equation 20.30 to calculate the index of refraction,
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This note was uploaded on 04/18/2010 for the course PHYS ? taught by Professor Zhou during the Spring '10 term at Georgia State University, Atlanta.

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Homework11-help - 20.12. Model: The wave is a traveling...

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