Homework 3 –Chapt. 23 & 22
23.64.
Model:
Use ray tracing to locate the image. Assume the converging lens is a thin lens.
Solve:
(a)
The figure shows the raytracing diagram using the steps of Tactics Box 23.2. After refraction, the three special rays
converge and give an image 50 cm away from the converging lens. Thus,
s
′
=
+
50 cm. The image is inverted and its height
is 0.65 cm.
(b)
Using the thinlens formula,
1
1
1
1
1
1
75 cm
30 cm
s
s
f
s
+
=
⇒
+
=
′
′
1
1
50 cm
s
⇒
=
′
⇒
50 cm
s
′ =
The image height is obtained from
50 cm
2
75 cm
3
s
M
s
′
= 
= 
= 
The image height is
(
)(
)
2/3
1 cm
0.67 cm.
h
Mh
′ =
= 
= 
Because of the negative sign, the image is inverted. These
results agree with those obtained in part (a).
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23.66.
Model:
Use ray tracing to locate the image. Assume the diverging lens is a thin lens.
Solve:
(a)
The figure shows the raytracing diagram using the steps of Tactics Box 23.3. After refraction from the diverging lens, the
three special rays do not converge. However, the rays appear to meet at a point that is 20 cm on the same side as the
object. So
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 Spring '10
 ZHOU
 1 cm, ray tracing, 3 Rad

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