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Unformatted text preview: Homework 3 Chapt. 23 & 22 23.64. Model: Use ray tracing to locate the image. Assume the converging lens is a thin lens. Solve: (a) The figure shows the ray-tracing diagram using the steps of Tactics Box 23.2. After refraction, the three special rays converge and give an image 50 cm away from the converging lens. Thus, s = + 50 cm. The image is inverted and its height is 0.65 cm. (b) Using the thin-lens formula, 1 1 1 1 1 1 75 cm 30 cm s s f s + = + = 1 1 50 cm s = 50 cm s = The image height is obtained from 50 cm 2 75 cm 3 s M s = - = - = - The image height is ( )( ) 2/3 1 cm 0.67 cm. h Mh = = - = - Because of the negative sign, the image is inverted. These results agree with those obtained in part (a). 23.66. Model: Use ray tracing to locate the image. Assume the diverging lens is a thin lens. Solve: (a) The figure shows the ray-tracing diagram using the steps of Tactics Box 23.3. After refraction from the diverging lens, the three special rays do not converge. However, the rays appear to meet at a point that is 20 cm on the same side as the three special rays do not converge....
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This note was uploaded on 04/18/2010 for the course PHYS ? taught by Professor Zhou during the Spring '10 term at Georgia State University, Atlanta.
- Spring '10