{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# note8 - MEEN 364 Notes for session on Notes from Session on...

This preview shows pages 1–3. Sign up to view the full content.

MEEN 364 Notes from Session on October 27, 2004 304 Fermier Hall, 6:00~7:00 pm 1 Notes for session on October 27, 2004. 1. The unit step response of the system described by the following block diagram is shown below it. Determine the values of the gains k 1 , k 2 , and the other pole of the plant, b . Also obtain the peak, rise, and settling time for 1% criterion. ( 2 (2 1 2 k sbs ++ 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.3 1.4 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.3 1.4 Step Response Time (sec) Amplitude d c b a

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
MEEN 364 Notes from Session on October 27, 2004 304 Fermier Hall, 6:00~7:00 pm 2 Solution: The transfer function is given by: ( 2 (2 1 12 1 2 () ( )2 22 k Ys TF R s sb s kk k s b s b kk == + ++ = ++ ++ (1) Since R(s) = 1 / s (unit step input), the steady state value of the output is: 1 0 lim 2 s k S S TF b kk + (2) From the figure for the step response, SS = 1, so, equation (2) becomes: 1 21 2 b k += (3) Now we compare equation (1) with the standard expression for the transfer function of a second order system, given in problem 1.a: 2 1 2 nn k k an db w zw + =+ (4)
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

note8 - MEEN 364 Notes for session on Notes from Session on...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online