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Unformatted text preview: ECE2011 HOMEWORK # 3 A09 Name : g H7“! ECE Box Number: This assignment is due Tuesday, Sept. 22, 2008, bring to class. Problem 1: Finding the Thevenin and Norton equivalent of simple circuits Solve the following problems by ﬁnding the Thevenin and Norton equivalent of of each network at
the terminals. You should do this by ﬁrst ﬁnding the short circuit current isc and the open circuit
voltage vac. In this problem you will show the most important steps of this process by writing out the equations
that you will solve, then the answers and then a check of the answers using the “source killing”
approach to ﬁnding RTH. Place your numerical answers on the lines provided to clearly identify the
six values: is“ you w, 11TH, RN and RTH in each of the solutions to help the graders. Thankyou. «r. 690; ’U'i"; iDV
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Wm Problem 2 ~ Finding the Norton and Thevenin equivalent Solve the following problems by ﬁnding the Thevenin and Norton equivalent of of each network at
the terminals. You should do this by ﬁrst ﬁnding the short circuit current isc and the open circuit voltage var, Again, place your numerical answers on the lines provided to clearly identify the six values: isc, vac,
iN, UTH, RN and RTH in each of the solutions to help the graders. In. 2011
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+ W 5v (Q MA), Problem 3 — Analyzing circuits with dependent sources Solve for the indicated voltages and currents in each of these circuits which have dependent sources.
Use Nodal analysis with the indicated ground as the reference. The ﬁrst step in dependent source
analysis involves expressing the contolled source’s value (of voltage or current) in terms of the named
nodal voltages and other circuit component values — Show in the space provided (ﬁrst in the list)
what that equation is in each case. Then show the nodal equations that can be used to solve the
circuit. Finally show your numerical solutions. (You might want to check the solutions you get
by entering these circuits into Qucs — that way you will know if you correctly expressed the nodal
equations.) 10 Points Extra if you attach printouts of your Qucs screens showing the circuits and
the solutions. «flux _/ d‘
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t /41 1 ~é 9+ Problem 4 W Voltage Division Solve for the indicated voltages in each case by applying voltage division. It may be necessary
sometimes to combine resistances in order to simply the circuit and to apply voltage division directly. 105‘» (43 aw (i Ion [011 “3,41 Problem 5 ,_ Current Division The Dual of voltage division is current division. Current division was not discussed in class, but
your textbook thoroughly discusses this analysis trick. Read the appropriate sections to extend
your knowledge. Then, solve for the indicated currents in each case by applying current division.
It may be necessary sometimes to combine resistances in order to simply the circuit and to apply
current division directly. {0 W,
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 Fall '08
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