1.20 - (c) What is the batterys rating in ampere-hours?...

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Problem 1.20 A 9-V flashlight battery has a rating of 1.8 kWh. If the bulb draws a current of 100 mA when lit, determine the following: (a) For how long will the flashlight provide illumination? (b) How much energy in joules is contained in the battery?
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Unformatted text preview: (c) What is the batterys rating in ampere-hours? Solution: (a) t = w p = W vi = 1 . 8 10 3 9 100 10-3 hours = 2 , 000 hours . (b) W = 1 . 8 10 3 3600 = 6 . 48 (MJ). (c) Ampere-hours = 1 . 8 kWh 9 V = . 2 (kAh)....
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This note was uploaded on 04/19/2010 for the course EE 220 taught by Professor Rawat during the Spring '09 term at Nevada.

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