2.36 - 2 2 2 2 R eq a c 2 8 2 R eq = 2 + 2 = 4 . (c) R eq a...

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Problem 2.36 For the circuit in Fig. P2.36, determine R eq at (a) Terminals ( a , b ) (b) Terminals ( a , c ) (c) Terminals ( a , d ) (d) Terminals ( a , f ) e f b a c d 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω 2 Ω Figure P2.36: Circuit for Problem 2.36. Solution: All resistances are in ohms. (a) b a 2 2 2 2 2 2 R eq b a 2 2 R eq = 1.5 6 2 6 + 2 R eq = 1 . 5 + 2 + 2 = 5 . 5 . (b) R eq a c 2 2
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Unformatted text preview: 2 2 2 2 R eq a c 2 8 2 R eq = 2 + 2 = 4 . (c) R eq a 2 2 2 2 2 d 2 R eq a 2 d 2 = 1.5 6 2 6 + 2 R eq = 2 + 2 + 1 . 5 = 5 . 5 . (d) R eq a 2 2 2 2 2 2 f 2 = 2 4 4 4 + 4 R eq a 2 f R eq = 2 + 2 + 2 = 6 ....
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