Ch_4_prob_0002

Ch_4_prob_0002 - ) 3 = 6 10 5 ( v p + 1 10 6 ) Hence, v p =...

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Problem 4.2 An op amp with an open-loop gain of 6 × 10 5 and V cc = 10 V has an output voltage of 3 V. If the voltage at the inverting input is 1 μ V, what is the magnitude of the noninverting-input voltage? Solution: v o = A ( v p v n
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Unformatted text preview: ) 3 = 6 10 5 ( v p + 1 10 6 ) Hence, v p = 3 6 10 5 1 10 6 = 4 V . All rights reserved. Do not reproduce or distribute. 2009 National Technology and Science Press...
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