Unformatted text preview: (b) acceptor concentration,N a =5x10 20 m-3 and (c) N d =7.5x10 16 m-3 and N a =5x10 16 m-3 . [Assume n i =1.2x10 16 m-3 ]. 3. Calculate the acceptor dopant density which is needed to fabricate a resistor of value 870 Ω in an integrated circuit. The resistors length and breadth are 50 μ m and 5 μ m respectively and the depth of diffusion can be assumed to be 2.5 μ m. [Hole mobility μ p =0.048m 2 V-1 s-1 ]....
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- Spring '10
- Integrated Circuit, 2mm, 1cm, 290K, 0.048m