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Unformatted text preview: (b) acceptor concentration,N a =5x10 20 m-3 and (c) N d =7.5x10 16 m-3 and N a =5x10 16 m-3 . [Assume n i =1.2x10 16 m-3 ]. 3. Calculate the acceptor dopant density which is needed to fabricate a resistor of value 870 in an integrated circuit. The resistors length and breadth are 50 m and 5 m respectively and the depth of diffusion can be assumed to be 2.5 m. [Hole mobility p =0.048m 2 V-1 s-1 ]....
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This note was uploaded on 04/19/2010 for the course IME 1009 taught by Professor Dr.bones during the Spring '10 term at Bangor University.
- Spring '10