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Unformatted text preview: rectangular tank is at z = 0, and the interfaces between the uids and the heights of the uids in the columns are as marked on the Fgure. The crosssectional area of the bottom of the tank is a . The dierence between this problem and the one we worked out in class is that the crosssectional area of the column on the left is A and on the right is 2 A . ind the values of z 1 , z 2 , z 3 , and z 4 . What is the pressure P in the uid on the righthand column at height z = ( z 1 + z 3 ) / 2? Be clever and minimize the algebra. 1...
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 Fall '08
 Morris
 Statics

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