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Unformatted text preview: rectangular tank is at z = 0, and the interfaces between the uids and the heights of the uids in the columns are as marked on the Fgure. The cross-sectional area of the bottom of the tank is a . The dierence between this problem and the one we worked out in class is that the cross-sectional area of the column on the left is A and on the right is 2 A . ind the values of z 1 , z 2 , z 3 , and z 4 . What is the pressure P in the uid on the right-hand column at height z = ( z 1 + z 3 ) / 2? Be clever and minimize the algebra. 1...
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- Fall '08