329sp10hw5sol - ECE 329 Spring 2010 Homework 5 - Solution...

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Unformatted text preview: ECE 329 Spring 2010 Homework 5 - Solution Due: Feb. 23, 2010 1. a) According to Page 2 in Lecture 11, the mobility is de ned as mobility = q m = q m . Although m is not explicitly given in the problem, it is related to N e and by (see Page 3 in Lecture 11) = N e q 2 m , or m = N e q 2 , therefore, mobility = q m = q N e q 2 = N e q = 5 . 8 10 7 8 . 45 10 28 1 . 6 10- 19 = 4 . 3 10- 3 ( m 2 / ( s V ) ) , where the unit is derived from v = q m E . b) R = l r 2 = 1000 5 . 8 10 7 (1 . 10- 3 ) 2 = 5 . 5 () . c) On the one hand, J = I r 2 . On the other hand, J = E. E = J = I r 2 = 1 5 . 8 10 7 (1 . 10- 3 ) 2 = 5 . 5 10- 3 ( V/m ) . d) The velocity of an electron is v = q m E = mobility E = 4 . 3 10- 3 5 . 5 10- 3 = 2 . 4 10- 5 ( m/s ) , so the time to drift from one end to the other is t = l v = 1000 2 . 4 10- 5 = 4 . 2 10 7 ( s ) ....
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This note was uploaded on 04/20/2010 for the course ECE ECE 329 taught by Professor Goddart during the Spring '10 term at University of Illinois at Urbana–Champaign.

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329sp10hw5sol - ECE 329 Spring 2010 Homework 5 - Solution...

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