329sp10hw6sol

329sp10hw6sol - ECE 329 Spring 2010 Homework 6 - Solution...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 329 Spring 2010 Homework 6 - Solution Due: Mar. 2, 2010 1. The magnetic eld at the origin is a superposition of those generated by the two sheets. a) Since the currents are owing in z direction and they extend to in nity in both x and z directions, the magnetic eld is in the x direction. The magnetic elds generated by the sheet y = 1 and y =- 1 are H 1 = 1 2 2 x = x ( A/m ) , H 2 = 1 - 2 2 x =- x ( A/m ) , respectively. Therefore, the total eld at the origin is H = H 1 + H 2 = ( A/m ) . b) Similar to a), we have H = H 1 + H 2 = 1 2 2 x + 1 - (- 2) 2 x = 2 x ( A/m ) . c) H = H 1 + H 2 = 1 - 2 2 y + 1 - 4 2 x + 1 2 2 y + 1 4 2 x = ( A/m ) . Note: Actually, we can directly obtain the results for a) and c) by using symmetry. 2. a) Biot-Savart law tells us that the direction of the magnetic eld generated by an in nitesimal current element is parallel to the cross product between the direction of the current and the vector joining the current element and the point under consideration. In our case, the current is parallel to y , then, using the right hand rule governing cross products, we can easily verify that in the region of z > along the z axis, B should be parallel to x : B || 2 y z...
View Full Document

Page1 / 5

329sp10hw6sol - ECE 329 Spring 2010 Homework 6 - Solution...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online