Chapter 11 Cornell Notes - 11.1 Rolling Motion of a Rigid...

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Chapters 11 – 14 Andre Mallqui 5 th Period 11.1 Rolling Motion of a Rigid Object - center of mass moves a linear distance so speed is = = = vmc dsdt R dθdt Rω - center of mass for rolling motion finds acceleration is = = acm dvcmdt = Rdωdt Rα - Kinetic energy is = K 12Ipω2 - Inertia is = + K 12ICMω2 MR2ω2 - kinetic energy is sum of rolling and translation kinetic energy Ex 11.1 Sphere Rolling Down an Incline -The potential energy is mgh and kinetic is zero so the change can find the acceleration, all acceleration and velocity of spheres are the same Ex 11.2 Another Look at the Rolling Sphere A FBD from the center of mass of the sphere can be used with torque to find the same acceleration 11.2 The Vector Product and Torque - origin is inertial frame, Newton’s law is true and vector product of r and F is used to find torque - this is not commutative but is distributive; preserve order of multiplication Ex 11.3 The Cross product A = 2i + 3j and B = -1i + 2j, cross product is7k for AxB and –BxA so they are equal
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Chapter 11 Cornell Notes - 11.1 Rolling Motion of a Rigid...

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