Assignment__1 - Assignment #1 8/18/04 PROBLEM 1.1 PROBLEM...

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Assignment #1 8/18/04 PROBLEM 1.1 PROBLEM STATEMENT: Determine the SI values for the following quantities: 6 ft, 200 lbm, 70 o F, 25 lbf/ft 2 , and 1 atm. GIVEN: 6 ft, 200 lbm, 70 o F, 25 lbf/ft 2 , and 1 atm. FIND: SI values for each of the given quantities ASSUMPTIONS: None. GOVERNING RELATIONS: 1. 1 ft = 0.3048 m 2. 1 lbm = 0.45359 kg 3. T( o F)= [1.8*T( o C)] + 32 4. 1 lbf/ft 2 =47.88 Pa = 47.88 N/m 2 5. 1 atm = 1.01325 bar = 101325 N/m 2 PROPERTY DATA: Not applicable QUANTITATIVE SOLUTION: 6 ft = 6 ft * 0.3048 m/ft = 1.8288 m 200 lbm = 200 lbm * 0.45359 kg/lbm = 90.72 kg 70 o F = 1.8 * T( o C) + 32 (70 – 32)/1.8 = 21.11 o C 25 lbf/ft 2 = 25 lbf/ft 2 * 47.88 (N/m 2 ) / (lbf/ft 2 ) = 1197 N/m 2 1 atm = 1.01325 bar = 101325 N/m 2 DISCUSSION OF RESULTS: Self-explanatory
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Assignment #1 8/18/04 PROBLEM 1.3 PROBLEM STATEMENT: The "British gravitational" system of units takes length, time, and force as the base units (foot, second and pound force, respectively.) Mass is a derived unit called a "slug"; one slug, when accelerated at 1 ft/s 2 , produces a force of 1 lbf. Define the relation between the slug and the length, time, and force units above and determine the value of the conversion factor g c for this unit system. GIVEN:
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Assignment__1 - Assignment #1 8/18/04 PROBLEM 1.1 PROBLEM...

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