Coefficient of Friction

Physics: Principles with Applications

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Colt Swayze Coefficient of Friction Data : Part 1: Weight in Wooden Box Force required N μ 100g 101.17 323.58 .3127 200g 131.17 423.58 .3097 300g 141.17 523.58 .2696 500g 171.17 723.58 .2366 700g 231.17 923.58 .2503 Weight on Small Block Force required N μ 100g 35 163.68 .2140 200g 45 263.68 .1707 300g 59.17 363.68 .1627 500g 94.17 563.68 .1668 700g 122.17 763.68 .1600 Weight on Large Block Force required N μ 100g 32 204.04 .1568 200g 40 304.04 .1316 300g 61.17 404.04 .1514 500g 86.17 604.04 .1427 700g 99.17 804.04 .1233 Weight on Steel Block Force required N μ 100g 158.17 902.6 .1752 200g 161.17 1002.6 .1608 300g 179.17 1102.6 .1625 500g 221.17 1302.6 .1698 700g 252.17 1502.6 .1678 Part 2: Sliding Object Wooden Box Small Block Large Block Steel Block Weight 223.58g 63.68 104.04 802.6 θ 1 18 15 13.5 10 θ 2 23 22 21 12.5 M k .3249 .2679 .2401 .1763 M s .4245 .4040 .3839 .2217 1 | P a g e
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Sample Calculations : Analysis and Conclusion : This experiment showed two different ways to calculate M or μ (upper and lowercase
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Unformatted text preview: Greek letter Mu). M is the slope of the line that gives the force required to move an object given its weight in N. Since we measured the weight of the object and also the force it took to move the object, we calculated Mu by dividing the force it took to accelerate away from zero by the weight of the object. In part two we calculated the same value by finding the angle at which had enough force to accelerate the object away from zero and the smallest angle at which the velocity would remain constant. To accelerate from zero was M s set equal to the tangent of the angle it took. The M k was the smallest angle it took to keep the object at a constant velocity....
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This note was uploaded on 04/21/2010 for the course PHYS 1004 taught by Professor Dr.good during the Spring '09 term at Ouachita Baptist.

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Coefficient of Friction - Greek letter Mu). M is the slope...

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