Mechanical Equivalent of Heat

Physics: Principles with Applications

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OUACHITA BAPTIST UNIVERSITY Mechanical Equivalent of Heat Intro. To Physics Monday Afternoon Lab Colt Swayze 12/2/2009
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Lab completed while partnering with Ashton Stewart on November 30, 2009 in the 3:00-4:50 Monday lab session.
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Data and Calculations :    Calculation of Work = ( + ) W Mg D1 D2 42πN = . × . ( . + . ) W 3 86439 9 8 0 04782 0 04850 42π887 Calculation of Heat absorbed = H mcTf - Ti . × . H 206 66g 0 22calg℃35℃ - 7℃
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= . . W 0 0963245573 2 = . W 5082 4 Nm = . × . H 206 66grams 6 16caloriesgrams = . H 1248 4 Calories Calculation of the Mechanical Equivalent of Heat (Joules) = J WH = . . J 5082 4 Nm1248 4 Calories = . Joules 4 0712 Results and Analysis :   The Joule equivalent of one calorie is 4.186 Joules.  4.186 J or one  calorie is the amount of Joules of heat it takes to raise one gram of water, one degree  Celsius.  In the data I collected it allowed me to calculate this value and the final answer I  calculated was 4.0712 J.  4.0712 J is only 2.74% off of the value considered to be exactly 
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Unformatted text preview: correct. This means that my measurements were precise and my calculations supported the already given value. The suggested question number three ask if the cylinder could absorb more heat than the work performed on it, the answer is no even if the room temperature is higher than the cylinder. The extra heat from the room temperature also is work it just won’t be accounted for in the calculations which could give these results. We also cannot determine the amount of mechanical energy that can possibly be produced from just our calculated value of J. There are many more variable that will affect this result so one constant will not come close to calculating an accurate answer....
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This note was uploaded on 04/21/2010 for the course PHYS 1004 taught by Professor Dr.good during the Spring '09 term at Ouachita Baptist.

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Mechanical Equivalent of Heat - correct This means that my...

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