Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PS04-1 MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.02 Spring 2010 Problem Set 5 Solutions Problem 1: Short Questions (a) Why is it possible for a bird to stand on a high-voltage wire without getting electrocuted? The reason is because the potential on the entire wire is nearly uniform, and the potential difference between the bird’s feet is approximately zero. Thus, the amount of current flowing through the bird is negligible, since the resistance through the bird’s body between its feet is much greater than the resistance through the wire between the same two points. (b) If your car’s headlights are on when you start the ignition, why do they dim while the car is starting? The starter motor draws a significant amount of current from the battery while it is starting the car. This, coupled with the internal resistance of the battery, decreases the output voltage of the battery below its the nominal 12 V. This decrease in voltage decreases the current through (and brightness of) the headlights. (c) Suppose a person falling from a building on the way down grabs a high-voltage wire. If the wire supports him as he hangs from it, will he be electrocuted? If the wire then breaks, should he continue to hold onto the end of the wire as he falls? As long as he only grabs one wire and does not touch anything that is grounded, he will be safe. If the wire breaks, let go! If he continues to hold on to the wire, there will be a large—and rather lethal—potential difference between the wire and his feet when he hits the ground. (d) A series circuit consists of three identical lamps connected to a battery as shown in the figure below. When the switch S is closed, what happens to the brightness of the light bulbs? Explain your answer. Closing the switch makes the switch and the wires connected to it a zero-resistance branch. All of the current through A and B will go through the switch and lamp C goes out, with zero voltage across it. With less total resistance, the current in the battery becomes larger than before and lamps A and B get brighter. PS04-2 Problem 2: Circuit The circuit below consists of a battery (with negligible internal resistance), three incandescent light bulbs (A, B & C) each with exactly the same resistance, and three switches (1, 2, & 3). In what follows, you may assume that, regardless of how much current flows through a given light bulb, its resistance remains unchanged. Assume that when current flows through a light bulb that it glows. The higher the current, the brighter the light will be. In each situation (a, b, c) as described below, we want to know which light bulbs are glowing (and which are not) and how bright they are (relative to each other). Always briefly discuss your reasoning....
View Full Document

This note was uploaded on 04/20/2010 for the course PHYS 8.02 taught by Professor Dourmashkin during the Spring '10 term at MIT.

Page1 / 15


This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online