Spring09_Test1_Key

# Spring09_Test1_Key - PGE 312 SPRING 2009 Physical and...

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PGE 312 - SPRING 2009 Physical and Chemical Behavior of Petroleum Fluids I Test #1, 50 Minutes Solution Key Problem 1 (25 points) Draw the structures of the five isomers of C 6 H 14 and name them according to the International Union of Pure and Applied Chemistry (IUPAC) naming rules. 1. Hexane CH 3 CH 2 CH 2 CH 2 CH 2 CH 3 2. 2- Methylpentane CH 3 3. 3- Methylpentane 4. 2,2- Dimethylbutane 5. 2,3- Dimethylbutane CH 3 CH CH 2 CH 2 CH 3 CH 3 CH 2 CH CH 2 CH 3 CH 3 CH 3 C CH 2 CH 3 CH 3 CH 3 CH 3 CH CH CH 3 CH 3 CH 3 1

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Problem 2 (25 points) 3 pounds of propane are held in a sealed container at 110 ° F. The volume of the container is 2 cubic feet. The physical properties of propane are as follows: Saturated liquid density at 110 ° F = 29.33 lb mass/cu ft Saturated vapor density at 110 ° F = 1.87 lb mass/cu ft Molecular weight = 44.097 lb mass/lb mole Critical pressure = 616.0 psia Critical specific volume = 0.0727 cu ft/lb mass Critical temperature = 206.06 ° F a. Calculate the volume of liquid propane in the vessel. The first step is to determine the state of the system using the given density information. 3 1.5 2 T m V ρ == = lb mass/cu ft, which is less than the saturated vapor density of 1.87 lb mass/cu ft. Because the total density of propane in the vessel is less than the saturated vapor density of propane at the given temperature, the system is all gas below its dew point. Therefore, the volume of liquid in the vessel is given by 0 L V = cubic ft
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Spring09_Test1_Key - PGE 312 SPRING 2009 Physical and...

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