Solutions_2 - EE 310 Problem Set No. 2 Solutions 2.8 (a) vs...

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Unformatted text preview: EE 310 Problem Set No. 2 Solutions 2.8 (a) vs (max) 12 2(0.7) 13.4 V 13.4 vs rms vs (rms) 9.48 V 2 (b) Vr C VM 2 f RC C VM 2 f Vr R C 2222 F 12 2 60 0.3 150 VM 1 R 12 1 150 (c) id , peak 2VM Vr 2 12 0.3 id , peak 2.33 A 2.15 (a) S 12.8 V N1 N2 120 2 12.8 13.3 (b) Vr 3% V r 0.03 12 0.36 V VO 11.82 V R 23.6 IL 0.5 A VM 12 C 11.8 mF 2 fRVr 2 60 23.6 0.36 VM 1 R 2VM Vr 12 1 23.6 2 12 0.36 (c) i D peak i D peak (d) i D avg i D avg 1 13.6 A 2Vr VM 1 VM R 2VM Vr 1 2 0.36 12 12 1 23.6 2 12 0.36 2 2 0.548 A (e) PIV 12.8 12 24.8 V EE 310 Problem Set No. 2 Solutions 2.22 a. II IL IZ 20 10 I I 45.0 mA 222 10 I L 26.3 mA 380 II IL I Z 18.7 mA b. PZ max I L min I L min RL 2k 400 mW I Z max 10 5 mA RL II I Z max 45 40 400 10 40 mA (c) For Ri 175 I Z max RL II 57.1 mA I L 26.3 mA IZ 30.8 mA 40 mA I L min 10 RL 585 17.1 57.1 40 17.1 mA EE 310 Problem Set No. 2 Solutions 2.24 (a) I L IZ 0 10 5.6 83.0 mA 50 3 5.6 0.083 3 5.85 V V L VZ PZ I Z VZ 0.083 5.85 0.486 W (b) 10 V L V L 5.6 V L 50 3 200 0.20 1.867 V L 0.02 0.3333 0.005 So V L 5.769 V 5.769 28.84 mA 0.2 10 5.769 84.62 mA II 0.050 And I Z I I I L 55.8 mA Then I L PZ 0.0558 5.769 0 12 5.6 50 3 V L 5.6 0.322 W (c) I L IZ 120.8 mA VZ PZ 0.1208 3 5.962 V 0.1208 5.962 0.72 W (d) 12 V L V L 5.6 V L 50 3 200 0.24 1.867 V L 0.02 0.333 0.005 So V L 5.88 V Then I L IZ PZ 5.88 12 5.88 29.4 mA; I I 0.20 0.05 122.4 29.4 93 mA 122.4 mA 0.093 5.88 0.547 W EE 310 Problem Set No. 2 Solutions 2.32 (a) V1 For vI vI vI vI 1 vI vI vI 1 15 5 V 3 5.7 V for vI 5.7, v0 vI V1 , v0 V1 0.7 1 1 v0 15 v0 0.7 1 2 1 15.7 0.7 111 v0 v0 2.5 2 1 121 1 8.55 v0 2.5 v0 vI 3.42 2.5 5.7 v0 5.7 15 v0 9.42 V1 0.7 15 V1 2 v0 0.7 (b) iD 0 for 0 vI 5.7 Then for vI 5.7 V iD vI 1 vO vI vI 3.42 2.5 1 iD 0.6vI 1 3.42 or For vI = 15, iD = 5.58 mA EE 310 Problem Set No. 2 Solutions 2.35 (a) (i) V B 5 V For I For I (ii) V B 5 V For I For I (b) (i) V B 5 V For I For I (ii) V B 5 V For I For I 2.36 a. V 0 5.7 V, 5.7 V, 4.3 V, 4.3 V, 4.3 V, 4.3 V, 5.7 V, 5.7 V, O O I 5.7 0 4.3 O O I 0 O O 0 I 4.3 O O 0 I 5.7 V 0.6 b. V 0 V 0.6 EE 310 Problem Set No. 2 Solutions 2.41 Circuit similar to Figure 2.31(a) with V B 2.44 a. I D1 V0 10 0.6 9.5 0.5 I D1 9.5 5 0.6 9.5 0.5 I D1 9.5 I D1 V0 0.94 mA 8.93 V ID2 0 10 V. b. I D1 V0 I D1 V0 0.44 mA 4.18 V ID2 0 c. d. Same as (a) 10 V0 I D1 I 2 0.5 0.6 I 9.5 V0 I 2 I D1 9.16 V ID2 0.482 mA I 0.964 mA I 9.5 ID2 2.53 a. R1 5 k , R2 D1 and D2 on I D1 I D1 10 k V0 0 1.86 1.0 10 10 0.7 0 5 10 0.86 mA b. R1 I V0 10 k , R2 10 0.7 IR2 5 k , D1 off, D2 on I D1 10 1.287 3.57 V 0 15 10 V0 ...
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This note was uploaded on 04/26/2010 for the course E E 310 taught by Professor Wharton,markjedwards,perrysto during the Spring '10 term at Pennsylvania State University, University Park.

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