Lecture 35

Lecture 35 - 4/12/10 e.g. A current of 10.0 A is passed...

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4/12/10 1 e.g. A current of 10.0 A is passed through an aqueous solution containing Ni 2+ for 12 minutes and 26 seconds. How many grams of Ni(s) is produced at the cathode? A) 4.53 g B) 2.27 g C) 0.0387 g D) 0.0773 g E) 4.38 ! 10 5 g 48 Ni 2+ + 2e- ! Ni (s) Eº = -0.257 V Grams Ni(s) = (0.0387 mol)(58.70g/mol) = 2.27 g Charge = (10.0 C/s)(746 s) = 7460 C Step 1: Find charge Step 2: Find moles of e - moles e - = (7460 C)/(96485 C/mol e - ) = 0.0773 mol Step 3: Find moles of Ni(s) moles Ni(s) = 0.0773 mol/2 = 0.0387 mol Step 4: Find grams of Ni(s) 5.6.A. Electroplating deposition of a thin layer of metal on electrode surface e.g. Electroplating Ni on steel Power source Ni steel NiCl 2 (aq) Ni 2+ Possible cathode reactions: 3. Cl 2 + 2 e- ! 2 Cl - +1.36 V 49 1. Ni 2+ + 2 e- ! Ni (s) -0.23 V 2. 2 H 2 O (l) + 2 e- ! H 2 (g) + 2 OH - - 0.83 V Possible anode reactions : 1. Ni 2+ + 2 e- ! Ni (s) -0.23 V 2. 4 H + (g) + O 2 (g) + 4 e- ! 2 H 2 O (l) +1.23 V 50 Reductions : Choose reactions with highest standard reduction potentials
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Lecture 35 - 4/12/10 e.g. A current of 10.0 A is passed...

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